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3 years ago

Gregory knows that Triangle A B C is reflected onto Triangle A prime B prime C prime. Which statement about the figures is true?

1 answer:

5 0

Answer: if Gregory draws the segment with endpoints A and A’, then the midpoint will lie on the line of reflection.

Explanation:

Given that a triangle ABC is reflected in triangle A'B'C'

Here reflection is done on a line

If you imagine the line as a mirror then ABC will have image on the mirror line as A'B'C'

Recall that in a mirror the object and image would be equidistant from the mirror and also the line joining the image and object would be perpendicular to the mirror

But note that corresponding images will only be perpendicular bisector to the line

So A and A' only will be corresponding so AA' will have mid point on line

Option 1 is right

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taurus [48]

Lets convert

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If rounded

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3 years ago

A housepainter mixed 5 gal of blue paint with every 9 gal of yellow paint in order to make a green paint. Which ratio of gallons

emmasim [6.3K]

The answer is 30:54.

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Andru [333]

Answer =-3 or -3/1

You can either do rise/run
Or you can find two points on the line and do (y2-y1)/(x2-x1)

Two points on the line are (-1,2) and (-3,-4)
X1=-1 Y1=2
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(y2-y1)/(x2-x1) = (-4-2)/(-3-(-1)) =(-6)/(-3+1)
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3 years ago

what are the ex and Y coordinates of point E, which partition the directed line segment from A to B into a ratio of 1:2?

Paul [167]

Answer:

Step-by-step explanation:

The formula for this is the one we use when we are given the ratio the directed line segment is separated into as opposed to the point being, say, one-third of the way from one point to another. The 2 equations we use to find the x and y coordinates of this separating point are:

$x=\frac{bx_1+ax_2}{a+b}$ and $y=\frac{by_1+ay_2}{a+b}$ where x1, x2, y1, y2 come from the coordinates of A and B, and a = 1 (from the ratio) and b = 2 (from the ratio). Filling in for x first:

$x=\frac{2(2)+1(-4)}{1+2}=\frac{4-4}{3}=0$ and then y:

$y=\frac{2(-3)+1(9)}{1+2}=\frac{-6+9}{3}=\frac{3}{3}=1$

The coordinates of point E, then, are (0, 1).

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3 years ago

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Dafna1 [17]

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