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gulaghasi [49]
3 years ago
15

Gregory knows that Triangle A B C is reflected onto Triangle A prime B prime C prime. Which statement about the figures is true?

Mathematics
1 answer:
ziro4ka [17]3 years ago
5 0
Answer: if Gregory draws the segment with endpoints A and A’, then the midpoint will lie on the line of reflection.

Explanation:

Given that a triangle ABC is reflected in triangle A'B'C'

Here reflection is done on a line

If you imagine the line as a mirror then ABC will have image on the mirror line as A'B'C'

Recall that in a mirror the object and image would be equidistant from the mirror and also the line joining the image and object would be perpendicular to the mirror

But note that corresponding images will only be perpendicular bisector to the line

So A and A' only will be corresponding so AA' will have mid point on line

Option 1 is right
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Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

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x = 0 → 4^{0} = 1 ⇒ a = 1

x = 2 → 4^{-2} = \frac{1}{4^{2} } = \frac{1}{16}, hence

b = \frac{1}{16}

x = 4 → 4^{-4} = \frac{1}{4^{4} } = \frac{1}{256}, hence

c = \frac{1}{256}

6 0
3 years ago
SOLVE THIS PROBLEM ASAP
zepelin [54]

Answer:

5

Step-by-step explanation:

Use the exponent rule

Simplifying the top of the fraction

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Our simplified fraction is 5^6/5^5, which is just 5^6-5 which is 5^1 or 5.

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4 0
2 years ago
Read 2 more answers
How do I solve this
sdas [7]
\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\
\cfrac{2x}{x^2+2x-24}-\cfrac{x}{x^2-36}\quad 
\begin{cases}
x^2+2x-24\implies (x+6)(x-4)\\
--------------\\
x^2-36\implies x^2-6^2\\
(x-6)(x+6)
\end{cases}

\bf \cfrac{2x}{(x+6)(x-4)}-\cfrac{x}{(x-6)(x+6)}\impliedby 
\begin{array}{llll}
\textit{thus our LCD is}\\
(x-6)(x+6)(x-4)
\end{array}
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3 0
3 years ago
Need help with this question):​
Citrus2011 [14]
I’m not sure maybe someone else will help
3 0
3 years ago
(a+b)^2*(a-b)<br> please answer me fast ​
kondaur [170]

Answer:

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(a+b)^2

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5 0
3 years ago
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