The energy associated with the stone from a height of 7.70 m can be calculated by multiplying the mass, gravitational acceleration and height. We do as follows:
Energy = mgh
Energy at 7.70 m = m(9.81)(7.70) = 75.537m
Energy at 5.25 m = 0.5mv^2 =75.537m
v = 12.29 m/s
A) 392 N/m
The spring constant can be found by applying Hooke's Law:
F = kx
where
F is the force applied to the spring
k is the spring constant
x is the stretching of the spring
Here we have:
F is the weight of the block hanging from the spring, which is
The stretching of the spring is
Therefore its spring constant is
B) 17.5 cm
Now that we know the value of the spring constant, we can calculate the new stretching of the spring when a mass of m=3.0 kg is applied to it. In this case, the force applied on the spring is
Therefore the stretching of the spring is
And since the natural length of the spring is 10 cm, the new length will be
L = 10 cm + 7.5 cm = 17.5 cm
Answer:
A. Generator
Explanation:
An alternator which is also called a generator basically converts mechanical energy into electric energy.
An alternator is used in a vehicle to charge the battery. It supplies electric power to the automobile.It is attached to the engine and is driven by a belt system . When the alternator does not charge the battery, it can be understood that it is not working as it no longer recharges the battery, though the engine of the automobile runs.
Answer:
No, the car will not make it to the top of the hill.
Explanation:
Let ΔX be how long the slope of the hill is, Δx be how far the car will travel along the slope of the hill, Ф be the angle the slope of the hill makes with the horizontal(bottom of the hill), ki be the kinetic energy of the car at the bottom of the hill and vi be the velocity of the car at the bottom of the hill and kf be the kinetic energy of the car when it stop moving at vf.
Since Ф is the angle between the horizontal and the slope, the relationship between the angle and the slope and the height of the hill is given by
sinФ = 12/ΔX
Which gives you the slope as
ΔX = 12/sinФ
Therefore for the car to reach the top of the hill it will have to travel ΔX.
Ignoring friction the total work done is given by
W = ΔK
W = (kf - ki)
Since the car will come to a stop, kf = 0 J
W = -ki
m×g×sinФ×Δx = 1/2×m×vi^2
(9.8)×sinФ×Δx = 1/2×(10)^2
sinФΔx = 5.1
Δx = 5.1/sinФ
ΔX>>Δx Ф ∈ (0° , 90°)
(Note that the maximum angle Ф is 90° because the slope of a hill can never be greater ≥ 90° because that would then mean the car cannot travel uphill.)
Since the car can never travel the distance of the slope, it can never make it to the top of the hill.