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3 years ago

What is the difference between transverse waves and longitudinal waves?

Physics

2 answers:

netineya [11]3 years ago

4 0

Answer:

D.transverse waves move perpendicular and longitudinal waves move parallel to the direction of energy movement

Explanation:

Transverse wave : It is defined as the wave in which the the vibration of the particles of the medium through which the wave travel is perpendicular to the direction of motion of the wave. Example : electromagnetic wave

Longitudinal wave : It is defined as the wave in which the the vibration of the particles of the medium through which the wave travel is parallel to the direction of motion of the wave. example : Sound wave

Degger [83]3 years ago

3 0

D.transverse waves move perpendicular and longitudinal waves move parallel to the direction of energy movement..

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A proton is accelerated from rest through a potential difference V0 and gains a speed v0. If it were accelerated instead through

Svet_ta [14]

Answer:

The speed is $\sqrt{2}v_{0}$ .

(a) is correct option.

Explanation:

Given that,

Potential difference $V= V_{0}$

Speed $v = v_{o}$

If it were accelerated instead

Potential difference $V'=2V_{0}$

We need to calculate the speed

Using formula of initial work done on proton

$W = q V$

We know that,

$\Delta W=\Delta K.E$

$q V=\dfrac{1}{2}mv^2$

Put the value into the formula

$q V_{0}=\dfrac{1}{2}mv_{0}^2$

$v_{0}^2=\dfrac{2qV_{0}}{m}$ ....(I)

If it were accelerated instead through a potential difference of $2 V_{0}$ , then it would gain a speed will be given as :

Using an above formula,

$v_{0}'^2=\dfrac{2qV_{0}}{m}$

Put the value of $V_{0}$

$v_{0}'^2=\dfrac{2q\times2V_{0}}{m}$

$v_{0}'=\sqrt{\dfrac{4qV_{0}}{m}}$

$v_{0}'=\sqrt{2}v_{0}$

Hence, The speed is $\sqrt{2}v_{0}$ .

6 0

3 years ago

8. two +1 C charges are separated by 3000m. What is the magnitude of the electric force between them?

Sidana [21]

Answer:

1000 N

Explanation:

The magnitude of the electrostatic force between two charged object is given by

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb constant

q1, q2 is the magnitude of the two charges

r is the distance between the two objects

Moreover, the force is:

- Attractive if the two forces have opposite sign

- Repulsive if the two forces have same sign

In this problem:

$q_1=q_2=+1C$ are the two charges

r = 3000 m is their separation

Therefore, the electric force between the charges is:

$F=(9\cdot 10^9)\frac{(1)(1)}{3000^2}=1000 N$

8 0

3 years ago

A force of 20. newtons to the left is exerted on a cart for 10. seconds.

myrzilka [38]

OK. Thank you. That's an impulse of 200 Newton-sec to the left,
telling us that the cart's leftward momentum increases by 200 kg-m/s
(or its rightward momentum decreases by that amount).

Did you have a question to ask ?

7 0

3 years ago

The velocity of a 150 kg cart changes from 6.0 m/s to 14.0 m/s. What is the magnitude of the impulse that acted on it?

tensa zangetsu [6.8K]

M = 150 kg.

Final velocity, v = 14 m/s

Initial Velocity, u = 6 m/s

Impulse = <span> m(v - u)</span>

= 150*(14 - 6)

= 150*8 = 1200 kgm/s or 1200 Ns<span> </span>

3 0

3 years ago

what characteristic of uranus makes it stand out from all the other jovian planets?

Luba_88 [7]

Jovian planets are also known as gas giants and are the four outer planets Jupiter, Saturn, Uranus and Neptune. Uranus stands out from this group because of the tilt of its axis. Uranus is tilted on its side. Scientists speculate that this tilt may be as a result of a collision with a large body just after the planet was formed. Uranus is tilted 98 degrees compared to earth's 23 degrees.

6 0

3 years ago

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