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WITCHER [35]
3 years ago
14

Is mixture an example of water

Physics
2 answers:
Evgesh-ka [11]3 years ago
7 0
No I don't believe so
BabaBlast [244]3 years ago
6 0
No it is not a mixture of water
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I need help on a homework question.
Mama L [17]

Answer:

green

Explanation:

the the board is going to be green

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3 years ago
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yellow cab taxi charges a $1.75 flat rate in addition to $0.65 per mile. kim has no more than $10 to spend on a ride. how many m
Nat2105 [25]

Answer:

you could go 12 miles paying $7.80 and $1.75

So in total being $9.55

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3 years ago
Two forces are acting on an object as shown in Fig. on the right. What is the magnitude of the resultant force?
svetlana [45]

Answer:

185 N

Explanation:

Sum of forces in the x direction:

Fₓ = -(80 N cos 75°) + (120 N cos 60°)

Fₓ = 39.3 N

Sum of forces in the y direction:

Fᵧ = (80 N sin 75°) + (120 N sin 60°)

Fᵧ = 181.2 N

The magnitude of the net force is:

F = √(Fₓ² + Fᵧ²)

F = √((39.3 N)² + (181.2 N)²)

F = 185 N

8 0
3 years ago
A car accelerates from rest at a rate of 3 m/s² for 4 seconds. How far did the car travel?
Gnom [1K]
Distance= distance(initial)+v(initial)*t+0.5at^2
D=0+0*4+0.5*3*4^2
D=24 m
4 0
3 years ago
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A cyclist makes the following trip along two vectors; he travels 9km to the north and then travels 6km to the east​
elena-14-01-66 [18.8K]

Answer:

Final distance from the origin: 10.82 km. the vector points as shown in the attached image.

Angle with respect to the east: 56.31^o

Explanation:

Please refer to the attached image. The cyclist's trip is indicated with the green arrows (9 km to the north followed by 6 km to the east.

So his final position is at the tip of this last vector, and indicated by the orange vector drawn form the point where the trip starts to the cyclist's final location.

We observe that this orange vector is in fact the hypotenuse of a right angle triangle, and we can estimate the distance from the origin by the Pythagorean theorem:

d=\sqrt{9^2+6^2} \\d=\sqrt{81+36} \\d=\sqrt{117} \\d=10.82 \,\,km

Notice that this is NOT the actual number of km that the cyclist pedaled to reach the final point.

Now, to find the value of the angle \theta, we need to use trigonometry, and in particular the tangent function gives us the ratio between the side of the triangle "opposite" to the angle, divided the side "adjacent" to the angle:

tan(\theta)=\frac{opp}{adj} \\tan(\theta)=\frac{9}{6}\\tan(\theta)=\frac{3}{2}\\

Now we can find the value of the angle by using the arctan function:

tan(\theta)=\frac{3}{2} \\\theta=arctan(\frac{3}{2} )\\\theta= 56.31^o

6 0
3 years ago
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