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mr Goodwill [35]
3 years ago
12

A small mailbag is released from a helicopter that is descending steadily at 2.00 m/s. After 5.00s what is the speed of the mail

bag
Physics
1 answer:
grandymaker [24]3 years ago
7 0
The acceleration of gravity (on Earth) is 9.8 m/s² downward.

This means that every falling object gains 9.8 m/s more downward speed
every second that it falls.

In 5 seconds of falling, it gains (5 x 9.8 m/s) = 49 m/s of downward speed.

If it was already descending at 2.0 m/s at the beginning of the 5 sec,
then at the end of the 5 sec it would be descending at

                                 (2 m/s  +  49 m/s)  =  51 m/s .
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You drive your car at a speed 40km/h for 1 hour, then slow down to 30km/h for the next 20km. How far did you drive, and what was
Bingel [31]
Speed=distance/time, rearranging gives speed*time=distance therefore the first section of the journey yielded a total distance of 40km, the second journey was stated to be 20km which was completed in (20/30)*60=40minutes. Therefore the total journey was 60km which was completed in 1hr40 minutes so the average speed was (60/1.66..)=36km/h.
8 0
3 years ago
Please help me - i beg u
oksano4ka [1.4K]

Answer:

516526.863 m

Explanation:

From the question given above, the following data were obtained:

Acceleration due to gravity (g) = 2.24 m/s²

Mass (M) = 8.96×10²¹ Kg

Gravitational constant (G) = 6.67×10¯¹¹Nm²/Kg²

Radius (r) =?

The radius of the planet can be obtained as follow:

g = GM/r²

2.24 = 6.67×10¯¹¹ × 8.96×10²¹ / r²

2.24 = 5.97632×10¹¹ / r²

Cross multiply

2.24 × r² = 5.97632×10¹¹

Divide both side by 2.24

r² = 5.97632×10¹¹ / 2.24

r² = 2.668×10¹¹

Take the square root of both side

r = √2.668×10¹¹

r = 516526.863 m

Thus, the radius of the planet is 516526.863 m

8 0
3 years ago
How do we find work from a force-displacement graph when the force exerted<br> is not constant?
Artemon [7]

Answer:

Explanation:

Read forces directly from the graph.

Read displacements directly from the graph.

Use the area under the graph to find the work done by the force. This is equal to the kinetic or potential energy the object gains due to the application of the force.

6 0
3 years ago
Calculate the tension (in N) in a vertical strand of spiderweb if a spider of mass 5.00 ✕ 10-5 kg hangs motionless on it.
Mandarinka [93]

Answer:

4.9 x 10⁻⁴N

Explanation:

Given parameters:

Mass of the vertical strand of spiderweb  = 5 x 10⁻⁵kg

Unknown:

Tension in the vertical strand  = ?

Solution:

The tension is the vertical strand will be the weight of the strand.

  Weight of strand  = mg

m is the mass

g is the acceleration due to gravity = 9.8m/s²

Tension in the vertical strand  = 5 x 10⁻⁵kg  x 9.8m/s²

Tension in the vertical strand  = 4.9 x 10⁻⁴N

3 0
3 years ago
A sound wave has a frequency of 425 Hz. What is the period of this wave?
Serhud [2]
Period is 1/frequency
1/425 = 2.353ms
8 0
3 years ago
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