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mr Goodwill [35]
3 years ago
12

A small mailbag is released from a helicopter that is descending steadily at 2.00 m/s. After 5.00s what is the speed of the mail

bag
Physics
1 answer:
grandymaker [24]3 years ago
7 0
The acceleration of gravity (on Earth) is 9.8 m/s² downward.

This means that every falling object gains 9.8 m/s more downward speed
every second that it falls.

In 5 seconds of falling, it gains (5 x 9.8 m/s) = 49 m/s of downward speed.

If it was already descending at 2.0 m/s at the beginning of the 5 sec,
then at the end of the 5 sec it would be descending at

                                 (2 m/s  +  49 m/s)  =  51 m/s .
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How long does it take a vehicle to reach a velocity of 32 m/s if it accelerates from rest at a rate of 4.2 m/s^2?
Marta_Voda [28]

Answer:

7.62

Explanation:

because you have to divide 32/4.2

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4 0
3 years ago
If V has a magnitude of 14 units and the same direction qs a vector 3i+6j+2k find v​
melomori [17]

Answer:

v = 6i + 12j + 4k

Explanation:

Find the magnitude of the direction vector.

√(3² + 6² + 2²) = 7

Normalize the direction vector.

3/7 i + 6/7 j + 2/7 k

Multiply by the magnitude of v.

v = 14 (3/7 i + 6/7 j + 2/7 k)

v = 6i + 12j + 4k

7 0
3 years ago
A bus moving along a level road increases its speed from 20 m/s to 35 m/s in 15.0s. What is the car's acceleration?​
Ksju [112]

Explanation:

initial velocity U = 20m/s

Final velocity V = 35m/s

time = 15.0 secs

change in velocity = 35 - 15

= 20m/s

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a = (35-20)/15

a= 15/15

Hence, your acceleration is 1m/s^2

5 0
2 years ago
As an emergency vehicle approaches Bob and moves away from Jill, how does the actual frequency of the siren change? A) As an eme
Tamiku [17]
The correct answer is: 
<span>C) The actual frequency of the siren does not change despite appearances.

In fact, Bob will observe an increase in the apparent frequency as the emergency vehicle approaches him, while Jill will observe a decrease in the apparent frequency as the emergency vehicle moves away from him, because of the Doppler effect (the relative velocity between the observer and the source of the sound is changing), but this effect involves the apparent frequency, while the real frequency of the siren will remain the same.</span>
7 0
3 years ago
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One end of a string 4.32 m long is moved up and down with simple harmonic motion at a frequency of 75 Hz . The waves reach the o
max2010maxim [7]

To solve this problem, we will apply the concepts related to the kinematic equations of linear motion, which define speed as the distance traveled per unit of time. Subsequently, the wavelength is defined as the speed of a body at the rate of change of its frequency. Our values are given as,

\text{Length of the string} = L = 4.32 m

\text{Frequency of the wave} = f = 75 Hz

\text{Time taken to reach the other end} = t = 0.5 s

Velocity of the wave,

V = \frac{L}{t}

V = \frac{4.32 m}{0.5s}

V = 8.64m/s

Wavelength of the wave,

\lambda = \frac{V}{f}

\lambda = \frac{8.64m/s}{75Hz}

\lambda = 0.1152m

\lambda = 11.52cm

Therefore the wavelength of the waves on the string is 11.53 cm

4 0
3 years ago
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