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3 years ago

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A student must have an average for five test grades that is greater than or equal to 80% and less than 90% to receive a final gr

ade of
b. gabi's grades on the first four tests were 98, 76, 86 and 92. what range of grades on the fifth test would give her a b in the course?

1 answer:

Veronika [31]3 years ago

8 0

The answer is 100.Well at leasl i think it is

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Solve the following system of equations for y:<br> y = 2x + 6<br> 3x – 4y = -19

padilas [110]

Answer:

x = -1 ; y=4

Step-by-step explanation:

1. Use the substitution method and replace the <em>y</em> on the second equation with the first equation,

2. Solve for <em>x</em> (x=-1)

3. Plug <em>x</em> into the first equation to get <em>y</em>

<em />

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Slav-nsk [51]

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how do you write a linear equation when given a graph or table? and how do you analyze key features of a function when given its

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When given a graph or table, you first want to figure out the slope. Look at the graph or table, and see how much does y change when x change in a certain amount? You want it as a rise/run so if x increases 2 when y increases 3 then the slope would be 3/2.

Next, you want to find the y intercept.
Look at the y value when x is 0. If the y is -2 when x=0, then b=-2.

When given its graph, find a y value when x is 0. If the y is 4 when x=0 then b=4

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TRUE OR FALSE in JkL and PQR if J equals P & K. Equals Q

slava [35]

The answer is false.
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Meghan has two less dimes as she does nickels and one more than double the amount of quarters as she does nickels for a total of

defon

Answer:

The number of nickel = 3

Number of dime = 1

Number of quarter = 7

Step-by-step explanation:

Let us assume the number of nickels Meghan has = m

So, the number of dimes she has = m -2

And the number of quarters she has = 1 + 2 m

Now, the total amount she has = $2.00

1 nickel = $0.05 ⇒ m nickel = m ($0.05) = 0.05 m

1 dime = $0.10 ⇒ (m -2) dime = m-2 ($0.10) = 0.10 (m-2)

1 quarter = $0.25 ⇒ (1+ 2m) quarter = (1+ 2m) ($0.25) = 0.25 (1+2m)

So, according to the question:

Amount of (nickel + dime + quarter) = $2.00

⇒ 0.05 m + 0.10 (m-2) + 0.25 (1+2m) = 2

or, 0.05 m + 0.10 m - 0.20 + 0.25 + 0.5 m = 2

or, 0.65 m = 2 - 0.05

or, m = 1.95/0.65 = 3

or, m = 3

Hence, the number of nickel = 3

Number of dime = m -2 = 3-2 = 1

and Number of quarter = 2m + 1 = 7

8 0

4 years ago