All categories

2 years ago

Help me pleaseeeee!!!

Mathematics

2 answers:

charle [14.2K]2 years ago

7 0

Answer:

Quadrent 4

Step-by-step explanation:

the bottom left quadrent if quadrent 4 top right is 1 top left is 2 and bottom right is 3

Misha Larkins [42]2 years ago

5 0

Answer:

quadrant 4

Step-by-step explanation:

You might be interested in

Please help

Andreyy89

9514 1404 393

Answer:

y -1 = -1(x -2)

Step-by-step explanation:

The slope of the line through the two points can be found from the slope formula:

m = (y2 -y1)/(x2 -x1)

m = (5 -1)/(-2 -2) = 4/-4 = -1

The point-slope equation for a line through point (h, k) with slope m is ...

y -k = m(x -h)

You have (h, k) = (2, 1) and m = -1. Putting these values into the form gives ...

y -1 = -1(x -2)

_____

Additional comment

Your problem statement already has two of the three values filled in, so you only need to enter the x-coordinate of the first point: 2.

5 0

2 years ago

How do you find the limit?

coldgirl [10]

Answer:

2/5

Step-by-step explanation:

Hi! Whenever you find a limit, you first directly substitute x = 5 in.

$\displaystyle \large{ \lim_{x \to 5} \frac{x^2-6x+5}{x^2-25}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{5^2-6(5)+5}{5^2-25}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{25-30+5}{25-25}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{0}{0}}$

Hm, looks like we got 0/0 after directly substitution. 0/0 is one of indeterminate form so we have to use another method to evaluate the limit since direct substitution does not work.

For a polynomial or fractional function, to evaluate a limit with another method if direct substitution does not work, you can do by using factorization method. Simply factor the expression of both denominator and numerator then cancel the same expression.

From x²-6x+5, you can factor as (x-5)(x-1) because -5-1 = -6 which is middle term and (-5)(-1) = 5 which is the last term.

From x²-25, you can factor as (x+5)(x-5) via differences of two squares.

After factoring the expressions, we get a new Limit.

$\displaystyle \large{ \lim_{x\to 5}\frac{(x-5)(x-1)}{(x-5)(x+5)}}$

We can cancel x-5.

$\displaystyle \large{ \lim_{x\to 5}\frac{x-1}{x+5}}$

Then directly substitute x = 5 in.

$\displaystyle \large{ \lim_{x\to 5}\frac{5-1}{5+5}}\\

\displaystyle \large{ \lim_{x\to 5}\frac{4}{10}}\\

\displaystyle \large{ \lim_{x\to 5}\frac{2}{5}=\frac{2}{5}}$

Therefore, the limit value is 2/5.

L’Hopital Method

I wouldn’t recommend using this method since it’s too easy but only if you know the differentiation. You can use this method with a limit that’s evaluated to indeterminate form. Most people use this method when the limit method is too long or hard such as Trigonometric limits or Transcendental function limits.

The method is basically to differentiate both denominator and numerator, do not confuse this with quotient rules.

So from the given function:

$\displaystyle \large{ \lim_{x \to 5} \frac{x^2-6x+5}{x^2-25}}$

Differentiate numerator and denominator, apply power rules.

Differential (Power Rules)

$\displaystyle \large{y = ax^n \longrightarrow y\prime= nax^{n-1}$

Differentiation (Property of Addition/Subtraction)

$\displaystyle \large{y = f(x)+g(x) \longrightarrow y\prime = f\prime (x) + g\prime (x)}$

Hence from the expressions,

$\displaystyle \large{ \lim_{x \to 5} \frac{\frac{d}{dx}(x^2-6x+5)}{\frac{d}{dx}(x^2-25)}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{\frac{d}{dx}(x^2)-\frac{d}{dx}(6x)+\frac{d}{dx}(5)}{\frac{d}{dx}(x^2)-\frac{d}{dx}(25)}}$

Differential (Constant)

$\displaystyle \large{y = c \longrightarrow y\prime = 0 \ \ \ \ \sf{(c\ \ is \ \ a \ \ constant.)}}$

Therefore,

$\displaystyle \large{ \lim_{x \to 5} \frac{2x-6}{2x}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{2(x-3)}{2x}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{x-3}{x}}$

Now we can substitute x = 5 in.

$\displaystyle \large{ \lim_{x \to 5} \frac{5-3}{5}}\\

\displaystyle \large{ \lim_{x \to 5} \frac{2}{5}}=\frac{2}{5}$

Thus, the limit value is 2/5 same as the first method.

Notes:

If you still get an indeterminate form 0/0 as example after using l’hopital rules, you have to differentiate until you don’t get indeterminate form.

8 0

2 years ago

Elizabeth earned $150 a week tutoring . If he saved $75, what percent of the money he earned did he save

olga2289 [7]

Answer:

50%

Step-by-step explanation:

Cuz 75 is 1/2 of 150, so 1/2 is equal to 50%.

8 0

2 years ago

Can someone help me

algol [13]

Answer:

A)310.18g/mol

B)84.9947g/mol

C)108.01 g/mol

d)159.7g /mole(Approx)

e)Coc12 g/mol

f) A1(OH)3 g/mol

g)83.9949 g/mol

h)197.9 g/mol

i)18.01529 g/mol

Step-by-step explanation:

Hope u happy with my answer...

please mark me as brainlest

7 0

2 years ago

What is the rational expression in simplest form? State any restrictions on the variables.

allochka39001 [22]

According to the question, the given rational expression can be simplified which is as shown below:

Rational expression = $\frac{12-4x}{x^{2} -9}=\frac{4(3-x)}{(x-3)(x+3)}$

For the simplification of the given expression, calculate the factors of the numerator as well as denominator terms and divide them from each other. In this change the sign of the expression before dividing with each other.

Rational expression = $\frac{-4}{(x+3)}$

The rational expression are also known as polynomial expression. The highest degree of these expression is two. And these expression uses concept of factor rule.

Therefore, the final expression is $\frac{-4}{(x+3)}$

What is polynomial expression?

Polynomial expression are those equation whose highest degree is two. It is also called as quadratic equation. And it is simplified by performing the factors on the given expressions.

To learn more about the polynomial expression from the given link:

brainly.com/question/1280754

#SPJ4

4 0

1 year ago