Mars has a thinner atmosphere and it is further from the sun.
We want to know the amount of force that stretches the spring 0.22 m.
That force is the WEIGHT of the mass hung from it.
The weight of the mass is (mass) times (gravity).
To do that calculation, we need to know the value of gravity, but
gravity has different values on every planet. I shall assume that
this whole springy question is taking place on Earth, so that the
value of gravity is 9.8 m/s² .
The weight of the mass is (0.4 kg) x (9.8 m/s²) = 3.92 Newtons.
The spring constant is
(force/length of the stretch)
= (3.92 Newtons) / (0.22 meters)
= (3.92 / 0.22) Newtons/meter
= 17.82 N/m .
Answer:
A) F=650N
B) W=0J
C)
Explanation:
A) Considering the equation , we can calculate:
B) The work the wall does is 0J, because the fingers of the scater against it do not move. It's the muscles on his arm that do the work.
C)
499.15 is lines per millimeter needed in a diffraction grating if the lines are to be resolved in the second-order spectrum with a beam of width 0.10 mm.
the wave length of the sodium spectrum are λ1 = 589.0 nm and λ2 =589.59 nm
The resolving power of the grating is R = λ/Δλ =Nm.
Thus, the total number of lines needed on the grating to resolve the wavelengths in order m is
For the sodium doublet in the first order, N = λ /m(Δλ)
where λ = 589.0 nm , Δλ = 589.59 nm -589.0 nm = 0.59 nm
m = 2
The minimum number of lines in the grating
N = [589.0 nm] / [(2)( 0.59 nm )] = 499.15
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