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postnew [5]
3 years ago
8

An electric bulb marked 40W-200V is used in a circuit of supply voltage 100V. Now its power is:

Physics
1 answer:
svp [43]3 years ago
7 0

Answer:

Power of the bulb is 10 Watts.                

Explanation:

We have,

Power and voltage of electric bulb is 40 W and 200 V. Using this data we can find the resistance of the bulb.

Power, P=\dfrac{V^2}{R}

R is resistance

R=\dfrac{V^2}{P}\\\\R=\dfrac{(200)^2}{40}\\\\R=1000\ \Omega

The supplied voltage is 100 V.

Now power is given by :

P=\dfrac{V^2}{R}\\\\P=\dfrac{100^2}{1000}\\\\P=10\ W

So, now the power of the bulb is 10 Watts.  

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On earth, you swing a simple pendulum in simple harmonic motion with a period of 1.6 seconds. what is the period of this same pe
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The period of a simple pendulum is given by
T= 2 \pi  \sqrt{ \frac{L}{g} }
where
L is the pendulum length
g is the acceleration of gravity

If we move the same pendulum from Earth to the Moon, its length L remains the same, while the acceleration of gravity g changes. So we can write the period of the pendulum on Earth as:
T_e= 2 \pi \sqrt{ \frac{L}{g_e} }
where g_e is the acceleration of gravity on Earth, while the period of the pendulum on the Moon is
T_m= 2 \pi \sqrt{ \frac{L}{g_m} }
where g_m is the acceleration of gravity on the Moon. 

If we do the ratio of the two periods, we get
\frac{T_m}{T_e} =  \sqrt{ \frac{g_e}{g_m} }
but the gravity acceleration on the Moon is 1/6 of the gravity acceleration on Earth, so we can write g_e = 6 g_m and we can rewrite the previous ratio as
\frac{T_m}{T_e} = \sqrt{ \frac{6 g_m}{g_m} }=  \sqrt{6}

so the period of the pendulum on the Moon is
T_m =  \sqrt{6}  T_e =  \sqrt{6} (1.6 s)=3.9 s
8 0
4 years ago
The number 14 is the 'mass number'. What does it tell us about this isotope?​
Svetradugi [14.3K]

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3 years ago
A bus travels 300 km south along a straight path with an average velocity of 85 km/h to the south. The bus stops for 22 minutes.
Kruka [31]

a) Answer;

= 6.72 hours

Explanation and solution;

velocity = distance over time  

Since we know the velocity and the distance, we can simply calculate time  

For the first part  

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time = 3.53 hours  

Then there is a 22 min stop, which is the same as 0.37 hours  

so far the trip is:  

3.53 + 0.37 = 3.9 hours  

then for the last stretch:  

78 km/h = 220 km / time  

time = 2.82 hours  

So the total trip is:  

3.9 + 2.82  = 6.72 hours

b) Answer;  

=  77.38 km/hr

Explanation and solution;

we take the total distance divided by the total time to get the average.  

total distance = 300 km + 220 km = 520 km  

total time = 6.72 hours  

Average velocity = 520 km / 6.72 hours =  77.38 km/hr


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