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4 years ago

Why are large astronomical bodies round

2 answers:

8 0

I would have to go with gravity, as each object in this universe has some amount of gravity, even humans and creatures and plants.

when a rock is thrown into space, it will have to travels light years away and pull in thousands of other asteroids into yet sometimes this doesn't work and sometimes nothing will happen depending on the speed of how they are going.

collision of these rocks are also another cause to the round shape, remember these rocks could be thousands of millions of years old. and this would be easy for them to shape because of the amount of asteroids in space.

this shape is also by the gravity on it in of from it. though this rare and it will be called a meteorite.

-Dominant- [34]4 years ago

7 0

<span>Matter of all types have gravity, which causes it to attract to each other. The most efficient way for all this matter to congregate is the sphere. As they consolidate, they form the shape. As they compress, temperatures in the center of the mass start to go up and if it hits the proper point, it can ignite and become a star.</span>

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(WILL MARK BRAINLIEST AND 22pts) As the earth travels around the sun, the sun is always at one focus of an ellipse. What's at th

finlep [7]

Answer:

d. nothing

Explanation:

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3 years ago

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An electron enters a region of uniform perpendicular en and bn fields. it is observed that thevelocity nv of the electron is una

konstantin123 [22]

<span>v is perpendicular to both E and B and has a magnitude E/B</span>

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3 years ago

If you make multiple measurements of your height, you are likely to find that the results vary by nearly half an inch in either

Lisa [10]

Answer:

Height h= 1.7 m

Explanation:

Supposing we have to find height in meter.

1 feet = 0.3048 m

1 inch = 0.0254 m

Given that:

5 feet

= 5×0.3048

= 1.524 m

and 7 inch = 7×0.0254= 0.1778 m

Therefore total height of a man in meter

5 feet 7 inch = 1.5424+0.1778 =1.7 m

Height h= 1.7 m

8 0

3 years ago

The electrons in the beam of a television tube have a kinetic energy of 2.20 10-15 j. initially, the electrons move horizontally

dalvyx [7]

(a) The electrons move horizontally from west to east, while the magnetic field is directed downward, toward the surface. We can determine the direction of the force on the electron by using the right-hand rule:
- index finger: velocity --> due east
- middle finger: magnetic field --> downward
- thumb: force --> due north
However, we have to take into account that the electron has negative charge, therefore we have to take the opposite direction: so, the magnetic force is directed southwards, and the electrons are deflected due south.

b) From the kinetic energy of the electrons, we can find their velocity by using
$K= \frac{1}{2}mv^2$
where K is the kinetic energy, m the electron mass and v their velocity. Re-arranging the formula, we find
$v= \sqrt{ \frac{2K}{m} }= \sqrt{ \frac{2 \cdot 2.20 \cdot 10^{-15} J}{9.1 \cdot 10^{-31} kg} }=6.95 \cdot 10^7 m/s$

The Lorentz force due to the magnetic field provides the centripetal force that deflects the electrons:
$qvB = m \frac{v^2}{r}$
where
q is the electron charge
v is the speed
B is the magnetic field strength
m is the electron mass
r is the radius of the trajectory
By re-arranging the equation, we find the radius r:
$r= \frac{mv}{qB}= \frac{(9.1 \cdot 10^{-31} kg)(6.95 \cdot 10^7 m/s)}{(1.6 \cdot 10^{-19} C)(3.00 \cdot 10^{-5} T)}=13.18 m$

And finally we can calculate the centripetal acceleration, given by:
$a_c = \frac{v^2}{r}= \frac{(6.95 \cdot 10^7 m/s)^2}{13.18 m}=3.66 \cdot 10^{14} m/s^2$

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4 years ago

10 points and brainlyest if possible and right.

Delicious77 [7]

THE answer the table is holding the book up would be a normal force

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4 years ago