All categories

3 years ago

How can you tell if a christmas tree light bulb is burned out just by looking at it?

2 answers:

6 0

You can tell by making sure that the lights are unplugged and tighten lights then plug it in if I didn't work it's burnt :) hope it works

PSYCHO15rus [73]3 years ago

6 0

It usually has a black stain it looks darker then the others... or if you look closely into it u can see the little metal for the electricity broken

You might be interested in

Why does the amount of water that flows in a river change during the year?

Nina [5.8K]

Hey

in the summer it is because of the meting of snow
in the spring it is rain

hope l helped

8 0

4 years ago

An electron is confined in a harmonic oscillator potential well. What is the longest wavelength of light that the electron can a

kipiarov [429]

Answer:

The longest wavelength of light is 209 nm.

Explanation:

Given that,

Spring constant = 74 N/m

Mass of electron $m= 9.11\times10^{-31}\ kg$

Speed of light $c= 3\times10^{8}\ m/s$

We need to calculate the frequency

Using formula of frequency

$f =\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}$

Where, k= spring constant

m = mass of the particle

Put the value into the formula

$f=\dfrac{1}{2\pi}\sqrt{\dfrac{74}{9.11\times10^{-31}}}$

$f=1.434\times10^{15}\ Hz$

We need to calculate the longest wavelength that the electron can absorb

$\lambda=\dfrac{c}{f}$

Where, c = speed of light

f = frequency

Put the value into the formula

$\lambda =\dfrac{3\times10^{8}}{1.434\times10^{15}}$

$\lambda=2.092\times10^{-7}\ m$

$\lambda=209\ nm$

Hence, The longest wavelength of light is 209 nm.

6 0

3 years ago

A department store sells an ""astronomical telescope"" with an objective lens of 30 cm focal length and an eyepiece lens of foca

Yuliya22 [10]

Answer:

The magnifying power of this telescope is (-60).

Explanation:

Given that,

The focal length of the objective lens of an astronomical telescope, $f_o=30\ cm$

The focal length of the eyepiece lens of an astronomical telescope, $f_e=5\ mm=0.5\ cm$

To find,

The magnifying power of this telescope.

Solution,

The ratio of focal length of the objective lens to the focal length of the eyepiece lens is called magnifying of the lens. It is given by :

$m=\dfrac{-f_o}{f_e}$

$m=\dfrac{-30}{0.5}$

m = -60

So, the magnifying power of this telescope is 60. Therefore, this is the required solution.

7 0

3 years ago

what is the average speed of a car that travels 40mph for 1 hour and 60 mph in another hour PLEASE HELP WILL MARK BRAINLIEST

suter [353]

Average speed = (distance covered) / (time to cover it)

-- Traveling at 40 mph for 1 hour, the distance covered is 40 miles.

-- Traveling at 60 mph for 1 hour, the distance covered is 60 miles.

-- Total distance covered = (40 miles) + (60 miles) = 100 miles

-- Total time = (1 hour) + (1 hour) = 2 hours

-- Average speed = (100 miles) / (2 hours)

<em>Average speed = 50 miles per hour</em>

8 0

3 years ago

Why is the moon’s surface cratered, but the Earth’s is not

Scorpion4ik [409]

The comets hit the moon's surface because there is no atmosphere on the moon to protect it. The earth has an atmosphere so it is protected.

8 0

3 years ago