The graph of the function C(x) = −0.52x2 + 23x + 92 is shown. The function models the production cost, C, in thousands of dollar
s for a candle company to manufacture a candle, where x is the number of candles produced, in thousands:
graph of a parabola opening down passing through points negative 3 and 69 hundredths comma zero, zero comma 92, 6 and 84 hundredths comma 225, 22 and 11 hundredths comma 346 and 33 hundredths, 37 and 39 hundredths comma 225, and 47 and 92 hundredths comma zero
If the company wants to keep its production costs under $225,000, then which constraint is reasonable for the model?
0 ≤ x < 6.84 and 37.39 < x ≤ 47.92
−3.69 ≤ x ≤ 6.84 and 37.39 < x ≤ 47.92
−3.69 ≤ x ≤ 47.92
6.84 ≤ x ≤ 37.39
graph of a parabola opening down passing through points negative 3 and 69 hundredths comma zero, zero comma 92, 6 and 84 hundredths comma 225, 22 and 11 hundredths comma 346 and 33 hundredths, 37 and 39 hundredths comma 225, and 47 and 92 hundredths comma zero
If the company wants to keep its production costs under $225,000, then which constraint is reasonable for the model?
0 ≤ x < 6.84 and 37.39 < x ≤ 47.92
−3.69 ≤ x ≤ 6.84 and 37.39 < x ≤ 47.92
−3.69 ≤ x ≤ 47.92
6.84 ≤ x ≤ 37.39
2 answers:
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We need to start from the innermost parenthesis and work our way out.
The first parenthesis is . These are not like terms because one involves a variable, while the other is a constant term. Two terms are summable if they involve the same power(s) of the same variable(s).
So, we can take one step outwards, and we arrive to the square brackets. We have
and 2z and -13z are like terms, so we can sum them:
Finally we arrive to the whole expression, which is
Because, again, 5z and 11z were like terms.
So the car is moving at 651 revolutions per minute, with wheels of a radius of 18inches
so, one revolution, is just one go-around a circle, and thus 2π, 651 revolutions is just 2π * 651, or 1302π, the wheels are moving at that "angular velocity"
now, what's the linear velocity, namely, the arc covered per minute
well
now, how much is that in miles/hrs? well
let's keep in mind that, there are 12inches in 1foot, and 5280ft in 1mile, whilst 60mins in 1hr
thus
notice, after all the units cancellations, you're only left with mi/hrs
so, one revolution, is just one go-around a circle, and thus 2π, 651 revolutions is just 2π * 651, or 1302π, the wheels are moving at that "angular velocity"
now, what's the linear velocity, namely, the arc covered per minute
well
now, how much is that in miles/hrs? well
let's keep in mind that, there are 12inches in 1foot, and 5280ft in 1mile, whilst 60mins in 1hr
thus
notice, after all the units cancellations, you're only left with mi/hrs