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Alisiya [41]
4 years ago
11

Hi! I would like some help on these questions please?

Mathematics
2 answers:
natka813 [3]4 years ago
3 0
First one
eliminate q's
multiply 2nd equation by -1 and add to 2nd

5p-3q=-39
<u>2p+3q=-3 +</u>
7p+0q=-42

7p=-42
divide both sides by 7
p=-6
sub back

-2p-3q=3
-2(-6)-3q=3
12-3q=3
minus 12
-3q=-9
divide -3
q=3

p=-6
q=3







2nd one

eliminate y's
multiply first equation by -1 and add to 2nd

-4x+3y=-12
<u>7x-3y=3 +</u>
3x+0y=-9

3x=-9
divide both sides by 3
x=-3
sub back
4x-3y=12
4(-3)-3y=12
-12-3y=12
-3y=24
y=-8

(x,y)
(3,-8)
Nana76 [90]4 years ago
3 0
Below I attached the working out for both set of systems.

For the first, solution to the system is  p = -6 ; q = 3 
For the second, the solution to the system is  x = -3 ; y = -8


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Answer:

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3 years ago
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blsea [12.9K]
Solutions 

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