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2 years ago

7

The four swimmers listed in the table are trying out for the swim team. If 3 swimmers will make the team, how many combinations

of 3 swimmers are possible? 3

1 answer:

dolphi86 [110]2 years ago

5 0

Number of combinations =( 4 x 3 x 2) / (1 x 2 x 3) = 4

Answer: 4 Combinations

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A triangular bandana has an area of 38 square inches. The height of the triangle is 9

meriva

Answer:

Base=8.4 inches

Step-by-step explanation:

Area of triangular bandana is 38sq inches

Height of triangle is 9 inches

Area of ∆ =½×b×h

38=½×b×9

38×2=b×9

76/9=b

b=8.4 inches

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2 years ago

Doreen went to see her favorite sports team play. Her car can go 120 miles on one tank of gas. If she used 30% of a full tank of

son4ous [18]

Answer:

Doreen traveled 35 miles.

Step-by-step explanation:

5 to the power of 2 is 25

2 multiplied by 5 is 10

then you add the 2 numbers and you get 35

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2 years ago

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Which algebraic expression is equivalent to the expression below 6 parentheses 2x + 7 parentheses -5

Inga [223]

If I understand this, you have the equation 6(2x+7)-5. This is equal to 12x+37. Hope this helps.

8 0

3 years ago

How many solutions does this have

RSB [31]

Answer:

one solution

Step-by-step explanation:

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3 years ago

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Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$

NOTE: sin²θ + cos²θ = 1

$\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}$

$\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}$

$\dfrac{2sec^2\theta}{tan^2\theta-1}$

Left side = Right side <em>so proof is complete</em>

8 0

3 years ago

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