The current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.
<h3>What is current?</h3>
The current is given as the product of the charge with time. In the electrochemical analysis of the nickel, there will be a reduction of the nickel ion to nickel. The formation is given as:
There is the deposition of 1 mole of Ni with 2 electrons transfer. The transfer of charge for 1 mole that is 58.7 grams Nickel is:
The mass of Ni to be deposited is 1.22 grams. The charge required is given as:
The current required to transfer 4010.7 C of charge in 1800 seconds is given as:
Thus, the current required to accumulate the 1.22 grams of nickel in 0.5 hours is 2.23 A.
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Answer:
![[NO]=\frac{k_{-1}}{k_1} [N_2O_2]](https://tex.z-dn.net/?f=%5BNO%5D%3D%5Cfrac%7Bk_%7B-1%7D%7D%7Bk_1%7D%20%5BN_2O_2%5D)
Explanation:
Hello!
In this case, since the reaction may be assumed in chemical equilibrium, we can write up the rate law as shown below:
![r=-k_1[NO]+k_{-1}[N_2O_2]](https://tex.z-dn.net/?f=r%3D-k_1%5BNO%5D%2Bk_%7B-1%7D%5BN_2O_2%5D)
However, since the rate of reaction at equilibrium is zero, due to the fact that the concentrations remains the same, we can write:
![0=-k_1[NO]+k_{-1}[N_2O_2]](https://tex.z-dn.net/?f=0%3D-k_1%5BNO%5D%2Bk_%7B-1%7D%5BN_2O_2%5D)
Which can be also written as:
![k_1[NO]=k_{-1}[N_2O_2]](https://tex.z-dn.net/?f=k_1%5BNO%5D%3Dk_%7B-1%7D%5BN_2O_2%5D)
Then, we solve for the concentration of NO to obtain:
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Answer:
A. particles are the same.
Explanation:
Hello, since we are talking about the water, the molecules are quite equal.
Nonetheless, if you want to know it (because this is not in the answers), the particles move faster in the boiling water than in the ice, considering that in the boiling water there is a larger energy content, which allows the molecules to move faster (they "have" more energy). In addition, The molecules are closer in the ice because that is the only way for them to solidify (get together).
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Hey there!
<span>The extreme conditions in the Earth's interior.
4.1.13
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Hope this helps!
~~Cutelion918~~
