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svp [43]
3 years ago
12

PLEASE HELP! DUE IN 5 MINS!!

Chemistry
1 answer:
kondaur [170]3 years ago
3 0

Answer:

False

Explanation:

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What type of reaction is "Separating Water"?
Lostsunrise [7]

Answer:

Decomposition

3 0
2 years ago
Flourine is found to undergo 10% radioactivity decay in 366 minutes determine its halflife​
yuradex [85]

Answer:

\boxed{\text{2408 min}}

Explanation:

The integrated rate law for radioactive decay is

\ln\dfrac{N_{0}}{N_{t}} = kt

1. Calculate the decay constant

\begin{array}{rcl}\ln \dfrac{100}{90} & = & k \times 366\\\\1.054 & = & 366k\\\\k & = & \dfrac{1.054 }{366}\\\\k & = & 2.879 \times 10^{-4} \text{ min}^{-1}\\\end{array}\\\\

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k}\\\\t_{\frac{1}{2}} = \dfrac{\ln2}{2.879 \times 10^{-4} \text{ min}^{-1}} = \text{2408 min}\\\\\text{The half-life for decay is } \boxed{\textbf{2408 min}}

8 0
3 years ago
A substance made up of only one type of atom would be a
mezya [45]

Answer:

Element

Explanation:

Because elements can be made with only one atom the rest of the answers cant be

4 0
2 years ago
Explain the difference between the organism, population, and community levels of ecological organization
Naily [24]

Answer:

A population is a group of organisms belonging to the same species that live in the same area and interact with one another.

Explanation:

Levels of Ecological Organization

Level # 2. Population:

Level # 3. Community:

Level # 4. Ecosystem:

Level # 5. Biome:

Level # 6. Biosphere:

5 0
3 years ago
This reaction was at equilibrium when 0.2 atm of iodine gas was pumped into the container, what happened to the equilibrium and
n200080 [17]

Answer:

Q was < K. Partial pressure of hydrogen decreased, iodine increased

Explanation:

<em>After iodine was added the Q was [Select] K so the reaction shifted toward the Products [Select] ,The partial pressure of hydrogen [Select], Iodine [Select] |,and hydrogen iodide Decreased</em>

Based on the equilibrium:

H2(g) + I2(g) ⇄ 2HI(g)

K of equilibrium is:

K = [HI]² / [H2] [I2]

<em>Where [] are concentrations at equilibrium</em>

And Q is:

Q = [HI]² / [H2] [I2]

<em>Where [] are actual concentrations of the reactants.</em>

<em />

When the reaction is in equilibrium, K=Q.

But as [I2] is increased, Q decreases and Q was < K

The only concentration that increases is [I2], doing partial pressure of hydrogen decreased, iodine increased

7 0
3 years ago
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