For the answer to the question above,
a1 = 40
<span>a2 = 20 </span>
<span>a3 = 10 </span>
<span>.. </span>
<span>aN = (1/2^N-1) a1 { in general aN= (r^N-1) A1 </span>
<span>a5 = (1/2^4) 40 = 40/16 = 2.5
</span>
So the answer to your question is 2.5
I hope my answer helped you. Feel free to ask more questions. Have a nice day!
Answer:
2. the process of breeding only organisms with desirable traits
Step-by-step explanation:
Reorder both sides
3y-6x=9
7-4y-3x=9
Multiply both sides
-6x-3y=9
6x+8y=-4
Dived both sides
11y= 5
Y=5/11
Substitute the value of Y
-3x-4(5/11)
Equals —> -14/11
Answer : (5/11 , -14/11)
Answer: The numbers are 10 and 23
Step-by-step explanation:
Let the smaller number be x
And the larger number be y
Ist sentence;
1. The sum of two numbers is 33.
X + y= 33 .........eqn 1
2. second sentence
the larger number is 3 more than two times the smaller number.
Y = 3 +2x
Put y into eqn 1
X+ 3 +2x = 33
3x= 33- 3
3x= 30
X = 30/3
X= 10 and y= 3+ 2x
Y= 3+ 2(10)
Y = 3+ 20
Y= 23
Therefore the two numbers are 10 and 23
