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wel
2 years ago
7

I giveeeeee brainlilstttttt

Mathematics
2 answers:
sladkih [1.3K]2 years ago
8 0

Answer:

(-8,0) becomes (8,0)

(-8,8) becomes (8,8)

(-6,8) becomes (6,8)

(-6,0) becomes (6,0)

Step-by-step explanation:

when reflecting over the y-axis, you just flip the sign for the x part if the coordinate. and when reflecting over the x-axis, you flip the sign on the y part if the coordinate.

Nataly_w [17]2 years ago
4 0

Answer:

A (8,0)  

B (8,8)

C (6,8)

D (6,0)

Step-by-step explanation:

Im pretty sure your can just flip the negative signs for "x" cause your flipping it across the y axis which changes the sign.

You might be interested in
A product can be made in sizes huge, average and tiny which yield a net unit profit of $14, $10, and$5, respectively. Three cent
navik [9.2K]

Answer:

The model is:

z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃    to maximize

Subject to:

First center               X₁₁  +  X₂₁  + X₃₁  ≤  550

Second center         X₁₂  +  X₂₂  + X₃₂  ≤ 750

Third center               X₁₃  + X₂₃  + X₃₃  ≤ 275                  

22* X₁₁  + 16* X₂₁  + 9*X₃₁     ≤   11000

22* X₁₂  + 16* X₂₂  + 9*X₃₂   ≤   2700

22*X₁₃  + 16* X₂₃  +  9*X₃₃  ≤  3400

X₁₁  +  X₁₂  + X₁₃  ≤  710

X₂₁  + X₂₂ + X₂₃  ≤  900

X₃₁ + X₃₂ + X₃₃  ≤  350

2700*(X₁₁  +  X ₂₁  + X₃₁)  -  11000*(X₁₂ + X₂₂ + X₃₂) = 0

3400*(X₁₁  +  X ₂₁  + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0

Xij >= 0

Step-by-step explanation:

Let´s call Xij   product size i produced in center j

According to this, we get the following set of variable

X₁₁    product size huge produced in center 1

X₁₂    product size huge produced in center 2

X₁₃   product size huge produced in center 3

X₂₁   product size average produced in center 1

X₂₂   product size average produced in center 2

X₂₃   product size average produced in center 3

X₃₁  product size-tiny produced in center 1

X₃₂ product size-tiny produced in center 2

X₃₃ product size-tiny produced in center 3

Then Objective function is

z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃

Constrains

Center capacity

1.-   First center               X₁₁  +  X₂₁  + X₃₁  ≤  550

2.-   Second center         X₁₂  +  X₂₂  + X₃₂  ≤ 750

3.- Third center               X₁₃  + X₂₃  + X₃₃  ≤ 275

Water available

1.-  22* X₁₁  + 16* X₂₁  + 9*X₃₁     ≤   11000

2.-  22* X₁₂  + 16* X₂₂  + 9*X₃₂   ≤   2700

3.-   22*X₁₃  + 16* X₂₃  +  9*X₃₃  ≤  3400

Demand constrain

Product huge

X₁₁  +  X₁₂  + X₁₃  ≤  710

Product average

X₂₁  + X₂₂ + X₂₃  ≤  900

Product tiny

X₃₁ + X₃₂ + X₃₃  ≤  350

Fraction SP/CC must be the same

First and second centers  fraction SP/CC  

(X₁₁  +  X ₂₁  + X₃₁)/ 11000   =  (X₁₂ + X₂₂ + X₃₂)/ 2700

2700*(X₁₁  +  X ₂₁  + X₃₁)  -  11000*(X₁₂ + X₂₂ + X₃₂) = 0

First and third centers  fraction SP/CC  

(X₁₁  +  X ₂₁  + X₃₁)/ 11000   = ( X₁₃ + X₂₃ + X₃₃)/ 3400

3400*(X₁₁  +  X ₂₁  + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0

The model is:

z = 14* X₁₁ + 14*X₁₂ + 5*X₁₃ + 10*X₂₁ + 10*X₂₂ + 10*X₂₃ + 5*X₃₁ + 5*X₃₂ + 5*X₃₃

Subject to:

First center               X₁₁  +  X₂₁  + X₃₁  ≤  550

Second center         X₁₂  +  X₂₂  + X₃₂  ≤ 750

Third center               X₁₃  + X₂₃  + X₃₃  ≤ 275                  

22* X₁₁  + 16* X₂₁  + 9*X₃₁     ≤   11000

22* X₁₂  + 16* X₂₂  + 9*X₃₂   ≤   2700

22*X₁₃  + 16* X₂₃  +  9*X₃₃  ≤  3400

X₁₁  +  X₁₂  + X₁₃  ≤  710

X₂₁  + X₂₂ + X₂₃  ≤  900

X₃₁ + X₃₂ + X₃₃  ≤  350

2700*(X₁₁  +  X ₂₁  + X₃₁)  -  11000*(X₁₂ + X₂₂ + X₃₂) = 0

3400*(X₁₁  +  X ₂₁  + X₃₁) - 11000*( ( X₁₃ + X₂₃ + X₃₃) = 0

Xij >= 0

6 0
3 years ago
If point C is between A and B, then AC + CB=_____<br><br> A. ABC<br> B. BC<br> C. AB<br> D. CA
velikii [3]

The answer is C. AB. The total line segment is ACB, or AB, because C is in between A and B. If you are adding AC and CB together, you are adding the two parts of the line together.

I hope this helps :)

7 0
3 years ago
Which expression is equivalent to 4(3+5)-3.94?
Anna007 [38]

Answer:

4(3 + 5) - 3.94 \\ 4 \times 8 - 3.94 \\ 32 - 3.94 \\  = 28.06

3 0
3 years ago
Pls answer fast<br> (√3 + √11)² + (√3 - √11)²
Masja [62]

(√3 + √11)² + (√3 - √11)²

  • (a+b)² = a² + b² + 2ab
  • ( a - b )² = a² + b² - 2ab

<em>Now </em><em>,</em>

(√3 + √11)² + (√3 - √11)²

(3 + 11 + 2√3√11)+ (3 +11 - 2√3√11)

14 + 2√33+ 14 - 2√33

14 + 14 = 28

Hence , The value of (√3 + √11)² + (√3 - √11)² is 28 .

6 0
2 years ago
Read 2 more answers
Simplify 7x + 7 + 6x - 9.<br><br> 13x - 2<br> 13x + 2<br> 11x
nikklg [1K]
To do this you must combine like terms as follows.

7x + 6x = 13x
7 - 9 = -2 

Combine these together and you will get the following.

13 - 2 or -2 +13
7 0
3 years ago
Read 2 more answers
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