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2 years ago

Question is in picture posted but this needs 20 characters so here ya go

Mathematics

1 answer:

Katyanochek1 [597]2 years ago

3 0

Answer:

Step-by-step explanation:

The dilation with the center of dilation at the origin and scale factor of 4 has the rule

(x,y)→(4x,4y).

Thus,

A(-1,3)→A'(-4,12)
B(2,1)→B'(8,4)
C(-2,-1)→C'(-8,-4)

A'(-4,12) - option B

B'(8,4) - option C

C'(-8,-4) - option D

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How do you do it????

m_a_m_a [10]

Answer:find the slope

Step-by-step explanation:

I don't know if you know how to find the slope if not reply back. But that's what the equation wants you to do.

6 0

3 years ago

Riya got 10 correct answers and ten incorrect answers. what is her score if each correct answer is awarded with 3 marks and each

Natasha2012 [34]

Answer:

Step-by-step explanation:

Riyas score = ( correct answer × mark) + ( incorrect answer × mark lost )

= ( 3× 10) + ( -1 ×10 )

= 30 -10

=20

5 0

3 years ago

Mr. Stokes bought 6 1/2 pounds of meat for a party. He used 2 1/4 pounds of meat to make tacos. The rest he used to make 1/4 pou

krok68 [10]

9514 1404 393

Answer:

Step-by-step explanation:

The remaining amount of meat is ...

6 1/2 - 2 1/4 = 4 1/4 = 17/4 . . . pounds

The number of 1/4 pound burgers that can be made with that amount of meat is ...

(17/4)/(1/4) = 17/1 = 17

Mr. Stokes made 17 burgers.

6 0

2 years ago

Given: F(x) = x + 2 and G(x) = 3x + 5 (F - G) (x) = 1) 4 2) -3x - 3 3) -2x - 3

mamaluj [8]

This equation is telling you to subtract the value of f(x) from the value of g(x).

f(x)= x + 2
g(x) = 3x + 5

so x + 2 - 3x -5 = -2x-3

4 0

2 years ago

Help please solve <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1

Shkiper50 [21]

Answer:

$\displaystyle -\frac{1}{2} \leq x < 1$

Step-by-step explanation:

Inequalities

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

$\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0$

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

$\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0$

Simplifying by x-1 and taking x=1 out of the possible solutions:

$\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0$

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

$(6x^3+14x^2+10x+12)$

is always positive and doesn't affect the result. It can be neglected. The expression

$(x-\frac{1}{2})^2$

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

$\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0$

For the expression to be negative, both signs must be opposite, that is

$(x+\frac{1}{2})\geq 0, (x-1)$

$(x+\frac{1}{2})\leq 0, (x-1)>0$

Note we have excluded x=1 from the solution.

The first inequality gives us the solution

$\displaystyle -\frac{1}{2} \leq x < 1$

The second inequality gives no solution because it's impossible to comply with both conditions.

Thus, the solution for the given inequality is

$\boxed{\displaystyle -\frac{1}{2} \leq x < 1 }$

7 0

2 years ago