1.) The error is that she attached the
variable with the flat fee (which is
constant) and put the daily rent as a
constant (which is variable).
The correct equation is:
365+125x=250+175x
2.) N=5
3.) k=-35.
Explanation: Solution:
17k-6=37k+4 . 17k-37k=4+6 .
-27k=10 . k=10\cdot(7-2) . k=-35 .
4.)
![y = - \frac{9}{16}](https://tex.z-dn.net/?f=y%20%3D%20%20%20-%20%5Cfrac%7B9%7D%7B16%7D%20)
.
This means that all of the points are co-linear. This is because if EG is a segment that contains F, and EN is a segment that contains M, then there can be two different segments. However, for a point F on the first segment and a point M on a second segment be in the same line as an end point of one of the segments, the segments have to be co-linear. They overlap.
All positive numbers and zero. All positive numbers because any value that is absolute becomes positive.
For a fraction, if the denominator turns to 0, the fraction becomes undefined, and therefore, that's a restriction on a rational.
now, what values of "x" makes the denominator 0? let's check,
x+2 = 0
x = -2
so, if "x" ever becomes -2, then you'd get
![\bf \cfrac{x+9}{x+2}\implies \cfrac{x+9}{-2+2}\implies \implies \cfrac{-2+9}{-2+2}\implies \stackrel{und efined}{\cfrac{7}{0}}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7Bx%2B9%7D%7Bx%2B2%7D%5Cimplies%20%5Ccfrac%7Bx%2B9%7D%7B-2%2B2%7D%5Cimplies%20%5Cimplies%20%5Ccfrac%7B-2%2B9%7D%7B-2%2B2%7D%5Cimplies%20%5Cstackrel%7Bund%20efined%7D%7B%5Ccfrac%7B7%7D%7B0%7D%7D)
so, the domain, or values "x" can take on safely, are any real numbers EXCEPT -2.
What you do is to substitute the first number for x and the second for y:
(x+7)y=10
a):
(-9+7)*-5=10
(-2)*-5=10
10=10
yes, it's a solution!
b)
(-8+7)10=10
-1*10=10
-10=10
no, not a solution!
c) (-2+7)2=10
5*2=10
yes, a solution!!
d) (3+7)*5=10
50=10
no, not a solution!