Answer:
The answer is below
Step-by-step explanation:
The question is not complete. A complete question is in the form:
A letter is chosen at random from the letters of the word EXCELLENT. Find the probability that letter chosen is i) a vowel ii) a consonant.
Solution:
The total number of letters found in the word EXCELLENT = 9
i) The number of vowel letters found in the word EXCELLENT = {E, E, E} = 3
Hence, probability that letter chosen is a vowel = number of vowels / total number of letters = 3 / 9 = 1 / 3
probability that letter chosen is a vowel = 1/3 = 0.333 = 33.3%
ii) The number of consonant letters found in the word EXCELLENT = {X, C, L, L, N, T} = 6
Hence, probability that letter chosen is a consonant = number of consonant / total number of letters = 6 / 9 = 2 / 3
probability that letter chosen is a consonant = 2/3 = 0.667 = 66.7%
Answer:
125
Step-by-step explanation:
Divide 50 by the 4 acres which is 12.5, then times 12.5 by 10 acres.
Answer:
Okapi 290 kg
Llama 160 kg
Step-by-step explanation:
Let weight of each llama be
Let weight of each okapi be
<em>Given, combined weight of 1 okapi and 1 llama is 450, we can write:</em>
<em></em>
<em>Also, average weight of 3 llama is 190 more than the average weight of 1 okapi, thus we can write:</em>
<em></em>
Now, substituting 2nd equation into 1st equation, we can solve for weight of 1 llama:
Each llama weights 160 kg, now using this and plugging into 2nd equation, we get weight of 1 okapi to be:
Each okapi weigh 290 kg
Answer: Start with y2-y1/x2-x1
-4+7/-6+3
Answer=2.5 or 5/2
DONT TRUST ME THOUGH
Step-by-step explanation: