Answer:
61 , 63 , 65 , 67
Step-by-step explanation:
Let the least even number be denoted by x. The sum of the four consecutive even numbers would be:
(x) + (x + 2) + (x + 4) (x + 6) = 256
First, simplify. Combine all like terms:
x + x + x + x + 2 + 4 + 6 = 256
4x + 12 = 256
Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.
First, subtract 12 from both sides of the equation:
4x + 12 (-12) = 256 (-12)
4x = 256 - 12
4x = 144
Next, divide 4 from both sides of the equation:
(4x)/4 = (144)/4
x = 144/4
x = 61
61 is your first number. Find the next 3 consecutive numbers:
x = 61
x + 2 = 63
x + 4 = 65
x + 6 = 67
Check:
61 + 63 + 65 + 67 = 256
256 = 256
~
Five consecutive integers are:
n, n+1, n+2, n+3, n+4 the sum of which is:
5n+10=265 subtract 10 from both sides
5n=255, divide both sides by 5
n=51
Our fifth number was n+4 so the fifth number is 55
Answer:
the answer is 9/ 15
Step-by-step explanation:
Sin y = p / h
= 9/ 15 (from y reference )
cos x =b/h = 9 / 15
as from x reference b= 9
I hope this will be helpful to you
if yes give 5 star
Whats the model because 7/9 × 3/4= 7/12 which also equals to 21/36
as 7/12 is the simplified version of 21/36 but then for c 4×9 =36 so I'm a bit confused my self but here's a bit of a start
