1. Use the Pythagoras theorem
13^2 = x^2 + 5^2
solve for x and youll get the height of the roof.
2. let x = length of the rpoe)-
x^2 = 9^2 + 12^2
3. Pythagoras again
20^2 = x^2 + 12^2
The answer is one. anything squared to the zeroth is 1.
We have that
<span>question 1
Add or subtract.
4m2 − 10m3 − 3m2 + 20m3
=(4m2-3m2)+(20m3-10m3)
=m2+10m3
the answer is the option
</span><span>B: m2 + 10m3
</span><span>Question 2:
Subtract. (9a3 + 6a2 − a) − (a3 + 6a − 3)
=(9a3-a3)+(6a2)+(-a-6a)+(-3)
=8a3+6a2-7a-3
the answer is the option
</span><span>B: 8a3 + 6a2 − 7a + 3
</span><span>Question 3:
A company distributes its product by train and by truck. The cost of distributing by train can be modeled as −0.06x2 + 35x − 135, and the cost of distributing by truck can be modeled as −0.03x2 + 29x − 165, where x is the number of tons of product distributed. Write a polynomial that represents the difference between the cost of distributing by train and the cost of distributing by truck.
we have that
[</span>the cost of distributing by train]-[the cost of distributing by truck]
=[−0.06x2 + 35x − 135]-[−0.03x2 + 29x − 165]
<span>=(-0.06x2+0.03x2)+(35x-29x)+(-135+165)
=-0.03x2+6x+30
the answer is the option
</span><span>C: −0.03x2 + 6x + 30
</span><span>
</span>
The correct answer is tanx(1-secx)/(1+secx)(1-secx)
The relationship between space, time and velocity for a uniform motion is given by:
where
S is the distance covered
t is the time
v is the velocity
The plane in our problem has a velocity of
and so during a total time of t=4 h, the distance it covers is
therefore, 680 miles.
