Question

Find the area of the parallelogram that has adjacent sides Bold u equals 3 Bold i minus Bold j plus Bold ku=3i−j+k and Bold v equals 3 Bold j minus 2 Bold kv=3j−2k.

Answer 1

Answer:

10.86

Step-by-step explanation:

area of parallelogram is equal to║$u$×$v$║

solving

now we calculate the cross product

$\left[\begin{array}{ccc}i&j&k\\3&-1&1\\0&3&-2\end{array}\right]$

=$-1i-6j+9k$

the area of parallelogram is:

║$u$×$v$║=$=\sqrt{-1^2-6^2+9^2}$

           =10.86