Question

Answer this question fast please.

Answer 1

Answer:

$A=4x^5+16x^4+4x^3$

Step-by-step explanation:

The area of a trapezoid is found with the formula

$A=\frac{(B+b)h}{2}$

where B is the measurement of the longest side of the trapezoid (the largest base) and b is the measurement of the shortest side of the trapezium (the minor base), and h is the height. In this case we have:

$b=8x^2+3x\\B=2x^3-x\\h=4x^2$

so, substituting this values in the formula:

$A=\frac{(2x^3-x+8x^2+3x)(4x^2)}{2}$

Simplifying the expression and joining like terms

$A=\frac{(2x^3+8x^2+2x)(4x^2)}{2}$

Multiplying the numerator parentheses:

$A=\frac{8x^5+32x^4+8x^3}{2}$

dividing by 2:

$A=4x^5+16x^4+4x^3$

the simplified expression for the area of this trapezoid  is

$4x^5+16x^4+4x^3$