Question

It takes 12.5 mL of a 0.30 M HCl solution to neutralize 285 mL of NaOH solution.

Answer 1

Answer:

0.013 M NaOH

Step-by-step explanation:

HCL + NaOH = NaCL + water

The mole ratio of acid and base is 1:1

Molarity is equal to the moles of solute divided by the liters of solution

Solute mole = 12.5 × 10^-3 × 0.3

= 0.003075

To neutralize 0.00375mol of HCl, 0.00375 mol of NaOH will be required. Since molarity is moles per liter, divide this amount of moles by the volume in liters:

Molarity = 0.00375/285 × 10^-3

Molarity = 0.0131 M