So for this one, 240 is Two Thirds of 360, which means in a shape with 6 points, it would move four points counterclockwise.
This would move G to the point H
C. H
Answer:65
Step-by-step explanation:
<span>1.Rename with common denominators.
2.Regroup the first fraction.
3.Subtract the whole numbers and numerators.
<span>4.Simplify (if necessary)</span></span>
Before we begin, let's identify what kind of angles these are and are they related in any way?
These angles are both acute and they are both corresponding angles.
Corresponding angles are equal to each other, and we can use this fact to our advantage.
Since they are equal to each other, we can set the equations of 1 and 2 equal to each other. Like so,
1 = 2
83 - 2x = 92 - 3x
Now, we can solve for X by isolating it on one side.
83 - 2x = 92 - 3x
Add 3x to each side: (This basically moves the X on the right side to the left.)
83 - 2x + 3x = 92 - 3x + 3x
83 + x = 92
Subtract 83 on each side to isolate the X.
83 + x - 83 = 92 - 83
x = 92 - 83
x = 9
Therefore, X equals 9. To check our work, we can substitute X for 9.
83 - 2(9) = 92 - 3(9)
83 - 18 = 92 - 27
65 = 65 -
TRUE
So to conclude, Angle 1 is 65 degrees, Angle 2 is 65 degrees, and X equals 9.
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Answer:
1. A = 59
2. A = 43
Step-by-step explanation:
If we have a right triangle we can use sin, cos and tan.
sin = opp/ hypotenuse
cos= adjacent/ hypotenuse
tan = opposite/ adjacent
For the first problem, we know the opposite and adjacent sides to angle A
tan A = opposite/ adjacent
tan A = 8.8 / 5.2
Take the inverse of each side
tan ^-1 tan A = tan ^-1 (8.8/5.2)
A = 59.42077313
To the nearest degree
A = 59 degrees
For the second problem, we know the adjacent side and the hypotenuse to angle A
cos A = adjacent/hypotenuse
cos A = 15.3/21
Take the inverse of each side
cos ^-1 cos A = cos ^-1 (15.3/21)
A = 43.23323481
To the nearest degree
A = 43 degrees
