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tester [92]
3 years ago
15

How to subtract with renaming fractions

Mathematics
1 answer:
givi [52]3 years ago
3 0
<span>1.Rename with common denominators.
2.Regroup the first fraction.
3.Subtract the whole numbers and numerators.
<span>4.Simplify (if necessary)</span></span>
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What is the value of the digit Seven in the number 437,158,269 7 million 70 million 7 thousand 700 thousand
professor190 [17]
The answer is 7 million

4 0
3 years ago
4(m+2) rewrite using distributive property
STALIN [3.7K]
4m + 8

Hope this helps!

4m + 8 = 0

Subtract 8 from both sides.

4m = -8

Divide 4 from both sides.

m = -2
3 0
3 years ago
Read 2 more answers
How do you simplify:<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%28125%20%5E%7B2%7D%20%7D%20%29%20%20%20%5E%7B%20-%20
Nady [450]

Answer:

\huge\boxed{\sqrt{(125^2)^{-\frac{1}{3}}}=\dfrac{1}{5}}

Step-by-step explanation:

\sqrt{(125^2)^{-\frac{1}{3}}}\qquad\text{use}\ (a^n)^m=(a^m)^n\\\\=\sqrt{\left(125^{-\frac{1}{3}\right)^2}\qquad\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=125^{-\frac{1}{3}}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=\dfrac{1}{125^\frac{1}{3}}\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\=\dfrac{1}{\sqrt[3]{125}}=\dfrac{1}{5}\qquad\text{because}\ 5^3=125

5 0
3 years ago
What is24/3 as a mixed number
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24/3 in a mixed fraction is 8
7 0
3 years ago
(2x3z2)3 <br> ------------------ <br> x3y4z2 * (x-4z3)
Komok [63]
The rules of exponents tell you to add exponents in the numerator and subtract those in the denominator. A power of a power causes the exponent to be multiplied.

\dfrac{(2x^{3}z^{2})^{3}}{x^{3}y^{4}z^2x^{-4}z^{3}}=2^{3}x^{(3\cdot3-3-(-4))}y^{-4}z^{(2\cdot3-2-3)}\\\\=\dfrac{8x^{10}z}{y^{4}}
8 0
4 years ago
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