The capillary action helps sustain life on Earth by the uptake of food and water by plants. The correct answer is A.
Answer:
Frequency of long trait allele ![= 0.55](https://tex.z-dn.net/?f=%3D%200.55)
Frequency of long trait allele ![= 0.45](https://tex.z-dn.net/?f=%3D%200.45)
Explanation:
Given -
Total Number of birds - ![2000](https://tex.z-dn.net/?f=2000)
Let us assume the given population is in Hardy Weinberg's equation -
Frequency of individuals with birds having long tails is depicted by ![p^2](https://tex.z-dn.net/?f=p%5E2)
Frequency of individuals with birds having short tails is depicted by ![q^2](https://tex.z-dn.net/?f=q%5E2)
Frequency of individuals with birds having medium tails is depicted by ![2pq](https://tex.z-dn.net/?f=2pq)
Frequency of individuals with birds having long tails
![\frac{614}{2000} * 100\\= 30.7](https://tex.z-dn.net/?f=%5Cfrac%7B614%7D%7B2000%7D%20%2A%20100%5C%5C%3D%2030.7)
![p^2 = .307\\p = 0.554](https://tex.z-dn.net/?f=p%5E2%20%3D%20.307%5C%5Cp%20%3D%200.554)
Frequency of individuals with birds having short tails
![\frac{413}{2000} *100\\20.65](https://tex.z-dn.net/?f=%5Cfrac%7B413%7D%7B2000%7D%20%2A100%5C%5C20.65)
![q^ 2 = 0.2065\\q = 0.4544](https://tex.z-dn.net/?f=q%5E%202%20%3D%200.2065%5C%5Cq%20%3D%200.4544)
Rounding off the values of p and q we get
Frequency of long trait allele ![= 0.55](https://tex.z-dn.net/?f=%3D%200.55)
Frequency of long trait allele ![= 0.45](https://tex.z-dn.net/?f=%3D%200.45)
Sum of both p and q should be unity
![0.55+ 0.45 = 1](https://tex.z-dn.net/?f=0.55%2B%200.45%20%3D%201)
The fact that the two strands of DNA are complementary <span />
Answer: Yes, because marine wildlife interacts with other marine wildlife and plant systems underwater. We could learn to manage these environments just like we do on land.
Explanation: