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vodka [1.7K]
3 years ago
12

What number is 12% of 53

Mathematics
1 answer:
Afina-wow [57]3 years ago
8 0
You can work out the percentage on a calculator by doing:

53/100
=0.53

And hen multiplying 0.53 by 12 to get

6.36

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A bag contains 7 red marbles, 3 blue marbles, 1 green what is the prob. of choosing a marble not blue?
Alex787 [66]
3 marbles as there is only one green and there is three other blue marbles left and that answer is incorrect 

8 0
3 years ago
WILL GIVE BRAINLIEST: What is the local minimum value of the function g(x)=x^4-5x^2+4? (Round answer to the nearest hundredth)
IrinaK [193]

Answer:

Step-by-step explanation:

you can find where the first derivative is 0 to find the critical points

g'(x) = ( x^4 -5x^2 +4)' = 4x³-10x

g'(x) =0, make y =0 to find find where g'(x) is 0

4x³-10x =0 , factor 2x

2x(2x²-5)= 0 , each factor must be 0

2x= 0, so x= 0

2x²-5 =0, so x = ±√5/2

we now have 3 critical points -√5/2, 0, and √5/2

make intervals (-∞, -√5/2), (-√5/2, 0) , (0, √5/2) and (√5/2, +∞)

pick a point to test on each interval: -2, -1, 1 and 2 for example, and

calculate g'(x) = 4x³-10x at those points

for x= -2 we have 4(-2)³-10(-2) = -12 , negative number, decrease

for x= -1 we have 4(-1)³-10(-1) =6, positive number, increase

for x= 1 we have 4(1)³-10(1) = -6, negative number, decrease

for x= 2 we have 4(2)³-10(2) = 12, positive number, increase

we went from a decrease to an increase on intervals (-∞, -√5/2), (-√5/2, 0) so x= - √5/2 ≈ -1.58 is a minimum

we went from a decrease to an increase on intervals (0, √5/2), (√5/2, +∞) so

x= √5/2 ≈ 1.58 is a minimum as well

4 0
2 years ago
The coordinate plane below represents a town. Points A through F are farms in the town. graph of coordinate plane. Point A is at
gayaneshka [121]
I made my own graph using the given points. Pls. see attachment. 

<span>Part A: Using the graph above, create a system of inequalities that only contains points D and F in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above.

I used paint program to graph the points based on the given data. 
I used a ruler as guide as I draw my line containing both points D and F and extended the line outward.
The yellow lines above represents the shaded portion of the graph.

y = mx + b

b is the y-intercept. It is the value of y when x is 0. In this case, b = 3.5
m is the slope. It is the change in y divided by the change in x. 
point D (2,4) ; point F (-2,3)
change in y: 4 - 3 = 1
change in x: 2 - (-2) = 4
m = 1/4

y = 1/4 x + 3.5 

Since we are looking for a system of inequality and the portion shaded is in the upper part of the line, the value of y will be greater than or equal to.

y </span>≥ 1/4x + 3.5<span>

Part B: Explain how to verify that the points D and F are solutions to the system of inequalities created in Part A.

To check the solution given above. We will use the x values of points D and F and check whether its y values are equal to or greater than the solution.</span>

y ≥ 1/4x + 3.5

Point D (2,4) : x = 2 : y ≥ 1/4 * 2 + 3.5 → 0.5 + 3.5 → 4
Point F (-2.3): x = -2 ; y ≥ 1/4 * -2 + 3.5 → -0.5 + 3.5 → 3
<span>
Part C: Chickens can only be raised in the area defined by y > 2x − 2. Explain how you can identify farms in which chickens can be raised.

y > 2x - 2

We will get the coordinates of each point and see if its x value will generate the desired value of y.

A(2,-3) ; x = 2 : </span><span>y > 2(2) - 2 </span>→ 4 - 2 → 2 . DID NOT PASS. -3 is lesser than 2.<span>
B(-3,-4) ; x = -3 : y > 2(-3) - 2 </span>→ -6 - 2 → -8. PASSED. -4 is greater than -8.<span>
C(-4,2) ; x = -4 : y > 2(-4) - 2 </span>→ -8 - 2 → -10. PASSED. 2 is greater than -10.<span> 
D(2,4) ; x = 2 : y > 2(2) - 2 </span>→ 4 - 2 → 2. PASSED. 4 is greater than 2.<span>
E(3,1) ; x = 3 : y > 2(3) - 2 </span>→ 6 - 2 → 4. DID NOT PASS. 1 is lesser than 4.<span>
F(-2,3) ; x = -2 ; y > 2(-2) - 2 </span>→ -4 - 2 → -6. PASSED. 3 is greater than -6.

Among the farms, points B,C, D, and F can raise chickens based on the given system of linear inequality. 

4 0
3 years ago
The volume of the pyramid shown in the figure is cubic centimeters. If the slant height of the pyramid increases by 4 centimeter
Nostrana [21]

Answer:

Part a) The volume of the original pyramid is 15\ cm^{3}

Part b) The volume of the pyramid increases by  6\ cm^{3}

Step-by-step explanation:

<u><em>The complete question is</em></u>

Part 1) The volume of the pyramid shown in the figure is 9,15,21, or 63 cubic centimeters?. Part 2) If the slant height of the pyramid increases by 4 centimeters and its height increases by 2 centimeters, the volume of the pyramid increases by 6,9,12 or 21 cubic centimeters?

we know that

The volume of the pyramid is equal to

V=\frac{1}{3}Bh

where

B is the area of the base

h is the height of pyramid

see the attached figure to better understand the problem

Step 1

Find the volume of the original pyramid

the area of the base B is equal to

B=3^{2}=9\ cm^{2}\\h=5\ cm

substitute

V=\frac{1}{3}(9)(5)=15\ cm^{3}

Step 2

Find the volume of the new pyramid

B=9\ cm^{2} -------> the area of the base is the same

h=5+2=7\ cm ------> the height increase by

substitute

V=\frac{1}{3}(9)(7)=21\ cm^{3}

Subtract the original volume from the new volume

21\ cm^{3}-15\ cm^{3}=6\ cm^{3}

5 0
3 years ago
This is my problem. I need help ​
koban [17]

Answer:

1: -3

2: She gives him $3 per week

3: 18

4: How much money she initially borrowed

5: y = -3x + 18

7 0
2 years ago
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