Answer:
4x² (3x - 1)
Step-by-step explanation:
→ Find the LCM of 12 and 4
LCM = 4
→ Find the LCM of x³ and x²
LCM = x²
→ Combine both LCM's together to form the outside multiplier
4x² (? - ?)
→ Complete the operations of 12x³ ÷ 4x² to find the first ? and 4x² ÷ 4x² to find the second ?
12x³ ÷ 4x² = 3x
4x² ÷ 4x² = 1
→ Therefore,
∴ 4x² (3x - 1)
<h3>
Answer: C. x+9</h3>
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Explanation:
Think of two numbers that multiply to -36 and also add to 5. Put another way: think of two factors of -36 that add to 5.
Those two numbers are 9 and -4 since
9 times -4 = -36
9 plus -4 = 5
So we have x^2 + 5x - 36 factor into (x+9)(x-4)
x+9 is one factor
x-4 is the other factor
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Alternatively, you can use a graphing tool to locate the x intercepts, and that will in turn lead to the factorization. Or you could use the quadratic formula to get the job done. Completing the square is yet another tool to use. So there are multiple approaches.
We can solve it like:
3x^3+3x^2+x+1= (3x^3+3x^2)+(x+1)=
3x^2(x+1)+(x+1)=
= (x+1)(3x^2+1)
Have a good day
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