Start from the parent function 
In the first case, you are computing
In the second case, you are computing
![f(x+1)-2 /tex] There are two translation going on: when you transform [tex] f(x) \to f(x+k)](https://tex.z-dn.net/?f=%20f%28x%2B1%29-2%20%2Ftex%5D%3C%2Fp%3E%20%3Cp%3EThere%20are%20two%20translation%20going%20on%3A%20when%20you%20transform%20%5Btex%5D%20f%28x%29%20%5Cto%20f%28x%2Bk%29%20)
, you translate the function horizontally, 
units left if 
and units right if 
.
On the other hand, when you transform 
, you translate the function vertically, units up if and units down if .
So, the first function is the "original" parabola , translated 
units right and 
units up. Likewise, the second function is the "original" parabola , translated 
units left and 
units down.
So, the transformation from 
to 
is: go 
units to the left and units down
B. Decreases
(Hopefully I’m right!)
Nothing changes if you don't add anything.
Example:
10+10=20
20+0=20
nothing changes.
This system can be a bit tricky unless you write it out:
(2n + 2)(2n - 2) ~ First you have to take one variable and multiply it to each of the other two variables, like:
2n * 2n ~ And:
2n * -2 ~ This gives you:
4n^2 - 4n
Now we do this with the other:
2 * 2n
2 * -2
4n - 4
Now we combine them both while adding like terms:
4n^2 - 4
Therefore your answer is: A. 4n^2 - 4
(This is due to how when having the positive 4n subtracted by the negative it cancels it out. Leaving us with the remaining two terms left.)
I hope this helps, have a great rest of your day! ^ ^
~Ghostgate
