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GaryK [48]
3 years ago
6

which choices are equivalent to the fraction below? check all that apply. 9^3/9^3 A.9^1 B.1 C.0 D.9^6 E.9^0

Mathematics
1 answer:
svetoff [14.1K]3 years ago
5 0

Answer:

Answers B and E

Step-by-step explanation:

Regarding the fraction 9^3/9^3:  You'd find it much easier to reduce this or find an equivalent expression if you'd write the fraction vertically:

9^3

------- = 1 (Answer B); but 9^0 is also correct (Answer E)

9^3

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Answer:

Both College #1 and College #2 have the same “net price”

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Step-by-step explanation:

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3 years ago
There is a jar containing 80 all of which are either quarters or die the total value of the coins is $13 how many of each coin a
padilas [110]

Answer:

There are 33 quarters and 47 dimes

Step-by-step explanation:

Let the number of quarters be q.

Let the number of dimes be d.

There are 80 coins in total. Therefore:

q + d = 80 ________(1)

The total value of coins is $13.

The value of a quarter is $0.25 and the value of a dime is $0.10. This means that:

0.25q + 0.10d = 13 _____(2)

We have a system of equations:

q + d = 80 ________(1)

0.25q + 0.10d = 13 ____(2)

From (1):

q = 80 - d

Put this in (2):

0.25(80 - d) + 0.10d = 13

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Collecting like terms:

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3 0
3 years ago
Ignore this
marissa [1.9K]

Answer:

Thanks for free

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A rectangular playground is 10m longer than it is wide.The area of the playground is 1400m² Calculate the width and length of th
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Answer:

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We can rewrite this expression like this:

x^2 +10 x -1400 =0

And we can use the quadratic formula given by:

x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

Where a =1 , b=10 , c= -1400

And replacing we got:

x = \frac{-10 \pm \sqrt{10^2 -4(10)(-1400)}}{2*1}

And solving we got:

x_1 =32.75 , x_2 = -42.75

And since the value can't be negative the answer would be x = 32.75 and the value of y = 32.75+10 =42.75

Step-by-step explanation:

For this case we know that we have a rectangular playground and the area can be founded with this formula:

A = xy

Where x represent the width and y the length. From the problem we know that A =1400 m^2 and the heigth is 10m longer than the wide so we can write this condition as:

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And replacing this formula into the area we got:

1400 = x(x+10)= x^2 +10x

We can rewrite this expression like this:

x^2 +10 x -1400 =0

And we can use the quadratic formula given by:

x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

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And replacing we got:

x = \frac{-10 \pm \sqrt{10^2 -4(10)(-1400)}}{2*1}

And solving we got:

x_1 =32.75 , x_2 = -42.75

And since the value can't be negative the answer would be x = 32.75 and the value of y = 32.75+10 =42.75

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