Answer:
Both College #1 and College #2 have the same “net price”
This is going by the fact that the equivalent money which happens to remain after all the deductions had been made are same. <em>The gross amount, though quite different happens to be same in the available net amount for same education cost in both college.</em>
Step-by-step explanation:
Answer:
There are 33 quarters and 47 dimes
Step-by-step explanation:
Let the number of quarters be q.
Let the number of dimes be d.
There are 80 coins in total. Therefore:
q + d = 80 ________(1)
The total value of coins is $13.
The value of a quarter is $0.25 and the value of a dime is $0.10. This means that:
0.25q + 0.10d = 13 _____(2)
We have a system of equations:
q + d = 80 ________(1)
0.25q + 0.10d = 13 ____(2)
From (1):
q = 80 - d
Put this in (2):
0.25(80 - d) + 0.10d = 13
20 - 0.25d + 0.10d = 13
Collecting like terms:
-0.15d = 13 - 20
-0.15d = -7
d = -7 / -0.15
d ≅ 47
Therefore:
q = 80 - 47 = 33
There are 33 quarters and 47 dimes.
Answer:
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Step-by-step explanation:
Answer:

We can rewrite this expression like this:

And we can use the quadratic formula given by:

Where 
And replacing we got:

And solving we got:

And since the value can't be negative the answer would be x = 32.75 and the value of y = 32.75+10 =42.75
Step-by-step explanation:
For this case we know that we have a rectangular playground and the area can be founded with this formula:

Where x represent the width and y the length. From the problem we know that A =1400 m^2 and the heigth is 10m longer than the wide so we can write this condition as:

And replacing this formula into the area we got:

We can rewrite this expression like this:

And we can use the quadratic formula given by:

Where 
And replacing we got:

And solving we got:

And since the value can't be negative the answer would be x = 32.75 and the value of y = 32.75+10 =42.75