For this case, the first thing we must do is define variables.
We have then:
n: number of cans that each student must bring
We know that:
The teacher will bring 5 cans
There are 20 students in the class
At least 105 cans must be brought, but no more than 205 cans
Therefore the inequation of the problem is given by:
Answer:
105 <u><</u> 20n + 5 <u><</u> 205
the possible numbers n of cans that each student should bring in is:
105 <u><</u> 20n + 5 <u><</u> 205
I think the answer is number 3
Answer:
well i dont really get ehat yours saying but the qustions are
3x+y=5
3^1+1=5
and then
4z+2y=20
i think
4^6+2^6=20
Step-by-step explanation:
