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Mrac [35]
4 years ago
6

There are millions of different species of animals, plants, and microorganisms. Which of the following factors do biologists con

sider to be the most important when classifying organisms?
A. details of internal and external body structures
B. environmental conditions of the organisms' habitats
C. inherited and acquired behaviors
D. general appearance
Biology
2 answers:
ddd [48]4 years ago
8 0

The answer is A. Morphology/anatomy is considered more relevant than behavior or general appearance in the classification of organisms. It is due to these anatomical features that animals such as bats are classified differently from birds (with bats classified as mammals even though they fly like birds) due to differences in anatomical features like milk-producing glands and brain structure.






yulyashka [42]4 years ago
6 0

I believe its A -details of internal and external body structures

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The diagram shows a certain type of fungus growing on food.
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7. A type of cell division that results in diploid cells: [meiosis / mitosis
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Two different enzymes catalyze the same reaction and both exhibit the same Vmax. When Enzyme A was run with a 40 uM substrate, t
Vinil7 [7]

Answer:

a) k_m = 4.08 uM

  V_{max} = 20.07 uM/min

b) k_m = 8.16 uM

Explanation:

Given that:

For Enzyme A:

the substrate concentration [S] = 40 uM

the initial velocity rate v = 10 uM/min

when it was 4mM, v = 20 uM/min

i.e.

at 4mM = 4000 uM;

Using Michealis -menten equation;

when v = 10

V = \dfrac{V_{max}[S]}{k_m+[S]}

∴

10 = \dfrac{V_{max}\times 40}{k_m + 40}

10 (k_m + 40) = V_{max}40

40V_{max} -10k_m = 400 --- (1)

when v= 20

20= \dfrac{V_{max}\times 4000}{k_m + 4000}

20 (k_m + 4000) = V_{max}4000

4000V_{max} -20k_m = 8000 --- (2)

equating equation (1) and (2):

40V_{max} -10k_m = 400 --- (1)

4000V_{max} -20k_m = 8000 --- (2)

let multiply equation (1) by 100 and equation (2) by 1

4000V_{max} - 1000K_m = 4000

<u>4000V_{max} - 20 k_m = 8000     </u>

  0        -980k_m = 4000

k_m = 4000/-980

k_m = 4.08 uM

replacing the value of k_m into equation (1)

40{V_max } - 10(4.08) = 400

40{V_max } - 40.8 = 400

40{V_max } = 400 +  40.8

40{V_max } = 440.8

V_{max} = 440.8/40

V_{max} = 11.02 uM/min

b)

Since V_{max} of A ie equivalent to that of B; then:

V_{max} of B = 11.02 uM/min

Here;

[S] = 80  uM

V = 10 uM/min

∴

10 = \dfrac{11.02 \times 80}{k_m + 80 }

10(k_m +80) = 881.6

10k_m = 881.6  - 800

10k_m = 81.6

k_m = 81.6/10

k_m = 8.16 uM

8 0
3 years ago
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