Loss of Rb, an important part of the G1-S transition checkpoint, can result in uncontrolled cell cycle progression and cancer. All of the following would mimic loss of Rb except constitutively active Ras GTPase activating protein. Correct answer: letter E.
Constitutively active Ras GTPase activating protein would not mimic loss of Rb, because it would not directly result in uncontrolled cell cycle progression.
<h3>What is Retinoblastoma (RB)?</h3>
Rb is an important tumor suppressor protein that works to inhibit cell cycle progression by preventing the activation of E2F transcription factors. Constitutively active Ras GTPase activating protein would not directly interfere with the Rb-E2F pathway, which is necessary for uncontrolled cell cycle progression and cancer.
Learn more about the cell cycle:
brainly.com/question/2457509
#SPJ4
Because through natural selection, only the fittest survive. when the fittest come together and reproduce then the species continues and evolves with only the fittest and strongest genes.
Answer:not c
Explanation:
C is not the correct answer took the test
Answer:mitosis produces 2 diploid cells
Explanation:
Answer:
a) k_m = 4.08 uM
V_{max} = 20.07 uM/min
b) k_m = 8.16 uM
Explanation:
Given that:
For Enzyme A:
the substrate concentration [S] = 40 uM
the initial velocity rate v = 10 uM/min
when it was 4mM, v = 20 uM/min
i.e.
at 4mM = 4000 uM;
Using Michealis -menten equation;
when v = 10
![V = \dfrac{V_{max}[S]}{k_m+[S]}](https://tex.z-dn.net/?f=V%20%3D%20%5Cdfrac%7BV_%7Bmax%7D%5BS%5D%7D%7Bk_m%2B%5BS%5D%7D)
∴



when v= 20



equating equation (1) and (2):


let multiply equation (1) by 100 and equation (2) by 1
4000V_{max} - 1000K_m = 4000
<u>4000V_{max} - 20 k_m = 8000 </u>
0 -980k_m = 4000
k_m = 4000/-980
k_m = 4.08 uM
replacing the value of k_m into equation (1)
40{V_max } - 10(4.08) = 400
40{V_max } - 40.8 = 400
40{V_max } = 400 + 40.8
40{V_max } = 440.8
V_{max} = 440.8/40
V_{max} = 11.02 uM/min
b)
Since V_{max} of A ie equivalent to that of B; then:
V_{max} of B = 11.02 uM/min
Here;
[S] = 80 uM
V = 10 uM/min
∴

10(k_m +80) = 881.6
10k_m = 881.6 - 800
10k_m = 81.6
k_m = 81.6/10
k_m = 8.16 uM