Question

If the detector readings are proportional to the amplitude of the microwave E field, the data from the first polarization experiment should be proportional to cos(θ) where θ is the angle between transmitter and detector. If the readings are proportional to the energy stored in the E field, the readings should be proportional to cos2(θ). Based on your data, are the detector readings proportional to amplitude, energy, or neither?

Answer 1

Answer:

Fields and variables are proportional

Explanation:

To solve the problem we must first identify the Vector Intensity,

The intensity is given by:

$I = I_ {0} cos^2 (\theta)$

We also know that the change given by the Intensity is always the square of the amplitude,

This is,

$I = A ^ 2$

The intensity is proportional to the change exerted on $cos ^ 2 (\theta)$

That is to say that in turn the amplitus is proportional to the Intensity.

On the other hand, relating the two variables we have

$A ^ 2 = A ^ 2_ {0} cos ^ 2 \theta$

$A = A_ {0} cos \theta$

In this way we can conclude that the electric field of intensity is also proportional to $cos ^ 2 \theta$