Say we have a cylinder
that has a height of dx, we see that the cylinder has a volume of: <span>
<span>Vcylinder = πr^2*h = π(5)^2(dx) = 25π dx
Then, the weight of oil in this cylinder is:
Fcylinder = 50 * Vcylinder = (50)(25π dx) = 1250π dx.
Then, since the oil x feet from the top of the tank needs to
travel x feet to get the top, we have:
Wcylinder = Force x Distance = (1250π dx)(x) = 1250π x dx.
<span>Integrating from x1 to x2 ft gives the total work to be: (x1
= distance from top liquid level to ground level; x2 = distance from bottom
liquid level to ground level)</span>
<span>W = ∫ 1250π x dx
<span>W = 1250π ∫ x dx
W = 625π * (x2 – x1)</span></span></span></span>
<span>x2 = 14 ft + 15 ft = 29 ft</span>
x1 = 14 ft + 1 ft = 15
ft
<span>
W = 625π * (29^2 - 15^2)
<span>W = 385,000π ft-lbs
= 1,209,513.17 ft-lbs</span></span>
Answer:
1.5 A
Explanation:
Applying
V = IR'....................... Equation 1
make I the subject of the equation
I = V/R'.................. Equation 2
Where V = Voltage, I = current, R' = Total resistance.
From the question,
In a series connection,
R' = 0.2+0.3+0.5+5 = 6 ohm.
Given: V = 9V
Substitute into equation 2
I = 9/6
I = 1.5 A.
Note: Since all the resistors are connected in series, thesame current flows through them
Therefore the current flowing through the 5 ohm resistor = 1.5 A
Answer:
magnitude=2085.99 kg
direction angle= 23.18°
Explanation:
let the forces be x,y
x = 1670cos(90°+30°) i +1670sin(90°+30°) j,
y = 1250cos(-90°-60°) i +1250sin(-90°-60°) j
x = 1670cos(120°) i + 1670sin(120°) j,
y = 1250cos(-150°) i + 1250sin(-150°) j
resultant force = x+y
resultant force = 1670cos(120°) i +1670sin(120°) j + 1250cos(-150°) i +1250sin(-150°) j
taking i and j term together
resultant force = (1670cos(120°) +1250cos(-150°)) i +(1670sin(120°) +1250sin(-150°)) j
resultant force = -1917.53 i +821.26j
![magnitude=\sqrt {(-1917.532)^{2} + (821.26)^{2}}](https://tex.z-dn.net/?f=magnitude%3D%5Csqrt%20%7B%28-1917.532%29%5E%7B2%7D%20%2B%20%28821.26%29%5E%7B2%7D%7D)
magnitude=2085.99 kg
direction angle= ![tan^{-1}(\frac{821.26}{1917.53})](https://tex.z-dn.net/?f=tan%5E%7B-1%7D%28%5Cfrac%7B821.26%7D%7B1917.53%7D%29)
direction angle= 23.18°
The answer is B. Mohammed has less kinetic energy than Autumn. Why cuz its right.
We want to know what does the fact that Mercury has no atmosphere tell us. Since Mercury has no atmosphere it cant reflect a lot of sunlight that is hitting its surface. Its constantly being hit by solar wind. So Mercury reflects a small percentage of the sunlight that strikes it.