1. When the two cars have the same mass, what is true about their velocities?

One anthem of silicon can properly be combined in a compound with

Darya [45]

One atom of silicon can properly be combined in a compound withtwo atoms of oxygen to produce silicon dioxide because silicon is very similar to carbon, as it is in the same group as carbon is in, therefore, it is able to make four bonds.
Moreover, Silicon has 4 valence electrons. In order to form an ionic bond, silicon would have to gain or lose 4 electrons.

4 0

4 years ago

An inductor, battery, resistance, and ammeter and switch are connected in series. If the switch, initially open, is now closed,

Tanzania [10]

The question is incomplete. Here is the complete question.

An inductor, battery, resistance and ammeter and switch are connected in series. If the switch, initially open, is now closed, what is the current's final value?

a. zero

b. Battery voltage divided by inductance

c. battery voltage times inductance

d. battery voltage divided by resistance

Answer: d. battery voltage divided by resistance

Explanation: Resistance, voltage and current are related by Ohm's Law, which is explained as the current that passes through a conductor is directly proportional to the applied voltage. The constant of proportionality between them is Resistance.

Ohm's Law is represented by $V=R.I$

Inductor is a component that stores magnetic energy when electricity is applied to it.

Ammeter is an object constructed to measure electric current of a circuit and it is always connected in serie.

So, in the circuit, when the switch is closed, the "only way" for current to pass through is because of Ohm's Law, which means its magnitude will be:

$I=\frac{V}{R}$

Then, the correct alternative is d. voltage divided by resistance.

7 0

3 years ago

A uranium nucleus is traveling at 0.94 c in the positive direction relative to the laboratory when it suddenly splits into two p

Anettt [7]

Answer:

A u = 0.36c B u = 0.961c

Explanation:

In special relativity the transformation of velocities is carried out using the Lorentz equations, if the movement in the x direction remains

u ’= (u-v) / (1- uv / c²)

Where u’ is the speed with respect to the mobile system, in this case the initial nucleus of uranium, u the speed with respect to the fixed system (the observer in the laboratory) and v the speed of the mobile system with respect to the laboratory

The data give is u ’= 0.43c and the initial core velocity v = 0.94c

Let's clear the speed with respect to the observer (u)

u’ (1- u v / c²) = u -v

u + u ’uv / c² = v - u’

u (1 + u ’v / c²) = v - u’

u = (v-u ’) / (1+ u’ v / c²)

Let's calculate

u = (0.94 c - 0.43c) / (1+ 0.43c 0.94 c / c²)

u = 0.51c / (1 + 0.4042)

u = 0.36c

We repeat the calculation for the other piece

In this case u ’= - 0.35c

We calculate

u = (0.94c + 0.35c) / (1 - 0.35c 0.94c / c²)

u = 1.29c / (1- 0.329)

u = 0.961c

6 0

3 years ago

A uniform electric field of magnitude 375 n/c pointing in the positive x - direction acts on an electron, which is initially at

Finger [1]

(a) The force exerted by the electric field on the electron is given by the product between the electron charge q and the intensity of the electric field E:
$F=qE=(1.6 \cdot 10^{-19}C)(375 N/C)=6\cdot 10^{-17}N$
Under the action of this force, the electron moves by:
$\Delta x = 3.20 cm=0.032 m$
And the work done by the electric field on the electron is equal to the product between the magnitude of the force and the displacement of the electron. The sign has to be taken as positive, because the direction of the force is the same as the displacement of the electron, so:
$W=F \Delta x= (6\cdot 10^{-17}N)(0.032 m)=1.9 \cdot 10^{-18}J$

(b) The electron is initially at rest and it starts to move under the action of the electric field. This means that as it moves, it acquires kinetic energy and it loses potential energy. The change in potential energy is the opposite of the work done by the electric field:
$\Delta U = U_f - U_i = -1.9 \cdot 10^{-18} J$
Where Uf and Ui are the final and initial potential energy of the electron.

(c) For the conservation of energy, the sum of the kinetic energy and potential energy of the electron at the beginning of the motion and at the end must be equal:
$U_i + K_i = U_f + K_f$ (1)
where Ki and Kf are the initial and final kinetic energies.
The electron is initially at rest, so Ki =0, and we can rewrite (1) as
$U_i - U_f = - \Delta U = K_f = \frac{1}{2}m_e v_f^2$
and by using the mass of the electron me, we can find the value of the final velocity of the electron:
$v_f= \sqrt{ -\frac{2 \Delta U}{m_e} }= \sqrt{- \frac{2(-1.9 \cdot 10^{-18} J)}{9.1 \cdot 10^{-31} kg} } =2.04 \cdot 10^6 m/s$

7 0

3 years ago

A 7.5 nC point charge and a - 2.9 nC point charge are 3.2 cm apart. What is the electric field strength at the midpoint between

Oduvanchick [21]

Answer:

Net electric field, $E_{net}=91406.24\ N/C$