Answer:
Force, |F| = 2100 N
Explanation:
It is given that,
Water from a fire hose is directed horizontally against at a rate of 50.0 kg/s, 
Initial speed, v = 42 m/s
The momentum is reduced to zero, final speed, v = 0
The relation between the force and the momentum is given by :
|F| = 2100 N
So, the magnitude of the force exerted on the wall is 2100 N. Hence, this is the required solution.
Answer:
Option D, The equator gets more direct sunlight throughout the yea
Explanation:
Answer: as the public need for equal access for people with disabilities became understood, laws were enacted to mandate assistive technologies inclusion in almost all public spaces
Explanation: I just took the test but my teachers a füçkįñg čūńt so don't know if the this will help
<span>2002 seconds, or 33 minutes, 22 seconds.
First, let's calculate how many joules it will take to lift 78 kg against gravity for 1100 meters. So:
78 kg * 9.8 m/s^2 * 1100 m = 840840 kg*m^2/s^2
Now a watt is defined as kg*m^2/s^3, so a division of the required joules should give us a convenient value of seconds. So:
840840 kg*m^2/s^2 / 420 kg*m^2/s^3 = 2002 seconds.
And 2002 seconds is the same as 33 minutes, 22 seconds.</span>
Answer:
0.384c
Explanation:
To find the speed of the pursuit ship relative to the cruiser you use the following relativistic equation:
u': relative speed
u: speed of the pursuit ship = 0.8c
v: speed of the cruiser = 0.6c
c: speed of light
You replace the values of the parameters to obtain u':
Hence, the relative speed is 0.384c
