Answer:
Dose = 5.4 10⁻⁴ Sv
Explanation:
The radiation dose absorbed by the body is 81% of the incident radiation, which is the number of particles per energy of each particle
E = 0.81 n₀ E₀
E = 0.81 4.2 10⁹ 0.81 6.1 10⁻¹³
E = 2.075 10⁻³ J
Effective radiation dose
Dose1 = n x RBE
Dose1 = 2,075 10⁻³ 15
Dose1 = 3.1 10⁻² REM
The effective radiation dose in sievert
Dose = dose1 / m
Dose = 3.1 10⁻² / 57
Dose = 5.4 10⁻⁴ [j / kg]
Dose = 5.4 10⁻⁴ Sv
Answer:
Transmission of telephone signals
Explanation:
Fiber optics are used for the transmission of telephone signals.
Answer: 317.0 m/s
Explanation:
The motion of the bullet is a projectile motion, with:
- a uniform motion with constant speed v along the horizontal direction
- an accelerated motion with constant acceleration toward the ground
We know that the starting height of the bullet is h=1.4 m. If we consider the vertical motion only, the initial velocity is zero, so we can write:
The bullet reach the ground when y(t)=0, so the time taken is
During this time, the bullet travels d=168 m horizontally, so its horizontal speed (which is equal to the initial speed of the bullet) is given by
In a simple pendulum with no friction, mechanical energy is conserved. Total mechanical energy is a combination of kinetic energy and gravitational potential energy. As the pendulum swings back and forth, there is a constant exchange between kinetic energy and gravitational potential energy.
Answer:
Velocity of the fish relative to the water when it hits the water = 14.32 m/s along 77.91° below horizontal.
Explanation:
Vertical motion of fish:
Initial speed, u = 0
Acceleration, a = 9.81 m/s²
Displacement, s = 10 m
We have equation of motion, v² = u² + 2as
Substituting
v² = 0² + 2 x 9.81 x 10 = 196.2
v = 14 m/s
Final vertical speed = 14 m/s
Final horizontal speed = initial horizontal speed = 3 m/s
Final velocity = 3 i - 14 j m/s
Magnitude
Direction
Velocity of the fish relative to the water when it hits the water = 14.32 m/s along 77.91° below horizontal.