Answer:
The electron is 5.88 m far from origin when it momentarily stops.
Explanation:
The position of electron on x-axis is given by the equation:
x = 16 t
m __________ eqn(1)
The speed of particle can be found out by taking derivative of "x" with respect to "t"
V = dx/dt = 16[-t
+
]
V = 16
(1 - t)
Now, when the electron stops, its velocity becomes zero.
V = 0 = 16
(1 - t)
(1 - t) = 0
<u>Either</u>:
= 0
-t = ln(0)
t = infinity (Since, time can not be infinite, thus this answer is rejected)
<u>Or</u>: 1 - t = 0
<u>t = 1 sec</u>
Therefore, at t= 1 sec, the electron will stop momentarily.
Using t = 1 sec in eqn (1), we find the position of electron.
x = 16(1)
m
<u>x = 5.88 m</u>
<u></u>
Answer:
7.7 GJ
Explanation:
Kinetic wnergy is given by
KE=½mv²
Where KE denote kinetic energy, m is the mass of object and v is velocity. Normally, m is in Kg and v in m/s
Conversion
Given speed of satelite in km/h, we convert it into m/s by multiply by 1000/3600
20000*1000/3600=5555.5555555555
Rounded off, m=5555.56 m/s
Substituting 500 kg for m and 5555.56 m/s for v then
KE=½*500*5555.56²=7,716,061,728.4 rounded off as
KE=7.7 GJ
consider the motion of projectile A in vertical direction :
v₀ = initial velocity of projectile A in vertical direction = 0 m/s (since the projectile was launched horizontally)
a = acceleration of the projectile = g = acceleration due to gravity = 9.8 m/s²
t = time of travel for projectile A = 3.0 seconds
Y = vertical displacement of projectile A = height of the cliff = h = ?
using the kinematics equation along the vertical direction as
Y = v₀ t + (0.5) a t²
h = (0) (3.0) + (0.5) (9.8) (3.0)²
h = 44.1 m
Answer:
a) v = 75 ft / s
, b) v = 55 ft / s
, c) Δx = 1000 ft
Explanation:
We can solve this exercise with the expressions of kinematics
a) average speed is defined as the distance traveled in a given time interval
v = (x₂-x₁) / (t₂-t₁)
v = (550 - 400) / (10 -8)
v = 75 ft / s
b) we repeat the calculations for this interval
v = (550 - 0) / (10 -0)
v = 55 ft / s
c) we clear the distance from the average velocity equation
Δx = v (t₂ -t₁)
Δx = 100 (20-10)
Δx = 1000 ft