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mestny [16]
3 years ago
7

Read the following lines from Wordsworth's poem and answer the question.

Mathematics
2 answers:
zubka84 [21]3 years ago
5 0
You answer would be “ HILLS”
Hope it helps you!
Jet001 [13]3 years ago
3 0

Answer:

hills

yw lil bruh

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the perimeter of a rectangle is twice the sum of its length and it width. The perimeter is 16 meters ans its length is 2 meters
olganol [36]

Answer:

The length is 6 meters.

Step-by-step explanation:

If its width is x meters  then its length is 2x + 2 meters and we have the equation:

2x + 2(2x + 2) = 16

2x + 4x + 4 = 16

6x = 16 - 4

6x = 12

x = 2 meters.

Thus x is the width and the length is 2(2) + 2 = 6 meters.

6 0
3 years ago
different sizes of regular pentagons are used in a stained glass window.each small pentagon has side lengths of 4 inches and an
Liula [17]
The goal is to find the area of a pentagon with side length 8.

We can find the area of a pentagon very easily by splitting it up into 10 congruent right triangles with the apothem as the height. The base of one of these triangles would be 4. The base angle would be 54 degrees, because it's half of the angle of a regular pentagon.

Using trig we find that the height of this triangle/apothem of the pentagon is equal to 4tan(54 degrees), which is about 5.506.

The area of a triangle is bh/2, so...4*5.506/2 = 11.011 in².
Times 10 triangles is 110.11 in².

7 0
3 years ago
Points A, B, C, and D lie on line segment AD. If AB = x, BC = x + 3, CD = twice the length of BC, and AD = 53, what is the value
kirza4 [7]
Point A the beginning of line and point D end of the line segment 
So ,x+x+3 +2(x+3)=53
2x+3+2x+6=53
4x+9 =53
4x =44
x=11
length of BC is 2(11+3)=28

6 0
3 years ago
Read 2 more answers
The Surface Area of a square pyramid is 3600 ft2. The slant height is 80 feet and the base is 20 feet. At most how many 1 foot c
ella [17]

The number of 1 foot cubic blocks that can be stuffed in the pyramid are; 10,583 cubes

<h3>How to find the surface area of a Pyramid?</h3>

The equation for the surface area of a square pyramid is;

Surface area = A + 1/2·p·s

where;

A = area of base

p = perimeter

s = slant height

The volume of the pyramid = (1/3) × A × h

Where:

A = Area of the base = 20 × 20 = 400 ft²

h = The height of the pyramid = √((slant height)² - ((base side length)/2)²)

h = √(80² - (20/2)²) = 30√7

The volume of the pyramid = 1/3*400*30·√7 = 4000·√7 ft³ = 10,583.005 ft³

If the cubes are flexible, then there are approximately 10,583 cubes

For rigid cubes we have;

Given that the height of the pyramid = 30·√7

The slope of the pyramid = (30/10)√7 = 3·√7

A increase in height of 1 foot gives a reduction in width of 2/(3√7)

The bottom can hold 400 cubes, Then next layer can hold;

19 × 19 = 361

If we continue to iterate, we will get a total of approximately 9915 rigid cubes in the pyramid.

Read more about Pyramid Surface Area at; brainly.com/question/22744289

#SPJ1

4 0
2 years ago
The path of a ball kicked from the ground can be modeled by the equation y=−1/5(x−5)(x−20), where x and y are measured in feet.
Helen [10]

Answer:

Step-by-step explanation:

This is already factored for the zeros of the quadratic.  If x - 5 = 0 and x - 20 = 0 then x = 5 and 20.  The ball was kicked 5 feet out and landed at 20 feet down the field.  The difference is 15 feet.  That's how far the ball traveled from its initial position on the ground to its landing place.

So 15 feet from where it was kicked.

5 0
3 years ago
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