The vertex is (-1, 2).
The equation of parabola:
where (h, k) is the vertex
We have h = -1 and k = 2.
Substitute:
![x=(y-2)^2-1\ \ \ \ |+1\\\\(x+1)=(y-2)^2](https://tex.z-dn.net/?f=x%3D%28y-2%29%5E2-1%5C%20%5C%20%5C%20%5C%20%7C%2B1%5C%5C%5C%5C%28x%2B1%29%3D%28y-2%29%5E2)
Answer:
x>3
Step-by-step explanation:
did it show the number line she threw?
Multiply the numbers (2*2=4)
![=\frac{-7+\sqrt{7^2-4\cdot \:2\left(-5\right)}}{2\cdot \:2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B-7%2B%5Csqrt%7B7%5E2-4%5Ccdot%20%5C%3A2%5Cleft%28-5%5Cright%29%7D%7D%7B2%5Ccdot%20%5C%3A2%7D)
Apply the rule
![\sqrt{7^2+2\cdot \:4\cdot \:5}](https://tex.z-dn.net/?f=%5Csqrt%7B7%5E2%2B2%5Ccdot%20%5C%3A4%5Ccdot%20%5C%3A5%7D)
7^2 =49
![=\sqrt{49+2\cdot \:4\cdot \:5}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B49%2B2%5Ccdot%20%5C%3A4%5Ccdot%20%5C%3A5%7D)
Multiply
![\sqrt{49+40}](https://tex.z-dn.net/?f=%5Csqrt%7B49%2B40%7D)
Add
![\sqrt{89}](https://tex.z-dn.net/?f=%5Csqrt%7B89%7D)
![=\frac{-7-\sqrt{89}}{4}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B-7-%5Csqrt%7B89%7D%7D%7B4%7D)
Final solution: