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elixir [45]
2 years ago
9

Which equation has the same solution as 4-2 (1-5) = 1 – 19?

Mathematics
1 answer:
lesya [120]2 years ago
3 0
The answer will be D
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Write and simplify the equation you would use to solve the problem below.
Taya2010 [7]
12s + 5 = 77
12s = 77 - 5 = 72
s = 72/12
s = 6 ...//

Ans = C ... 12x + 5 = 77 ...
7 0
2 years ago
Which list contains only values equivalent to 3/10
bekas [8.4K]

Answer:

C

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Angle ABD and angle DBC are linear pairs, and angle ABD and angle EDC are vertical angles. If the measure of angle ABD=5(2x+1),
Ugo [173]
∠ ABD = 5(2X+1)
∠ DBC = 3X+6
∠ EBC = Y +135/2

∠ ABD and ∠ DBC are linear pairs
∴ ∠ ABD +∠ DBC = 180
∴ 5(2X+1) + 3X+6 =180
solve for x
∴ x = 13
∴∠ ABD = 5(2X+1) = 5(2*13+1) = 135
  ∠ DBC = 3x+6  = 3*13+6 = 45

∠ ABD  and ∠ EBC are vertical angles
∴ ∠ ABD = ∠ EBC = 135
∴ y +135/2 = 135
∴ y = 135/2

The <span>statements that are true:
--------------------------------------</span><span>
C.) x=13
E.)measure of angle EBC =135
F.) angle DBC and angle EBC are linear pairs </span>




8 0
3 years ago
Read 2 more answers
Francis went to the sporting goods store and spent $75.15 on 6 items.
MArishka [77]

Answer:

$6.03

Step-by-step explanation:

The question is asking us how much each pair of socks cost. With the information we are given, we know that there are 5 pairs and that they all cost the same amount. If the total were just the 5 socks, we could easily divide the total by 5 to get the price of each pair but that's not the case. The soccer ball is included in the final cost. To overcome this, we just have to subtract the soccer ball's cost ($45) from the total.

So we subtract $45 from $75.15, giving us $30.15, the total amount of all the socks. However we need to find out how much each pair costs and there are 5 of them, so we divide 30.15 by 5. This gives us the answer, $6.03.

Each pair of socks cost $6.03.

Simpler Explanation:

  • $75.15 - $45 = $30.15
  • $30.15 / 5 = $6.03

The answer is $6.03

5 0
3 years ago
Represent each of these relations on {1, 2, 3, 4} with a matrix (with the elements of this set listed in increasing order). a) {
Irina-Kira [14]

Answer:

for a  a) {(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)}

\left[\begin{array}{cccc}0&1&1&1\\0&0&1&1\\0&0&0&1\\0&0&0&0\end{array}\right]

for b

b) {(1, 1), (1, 4), (2, 2), (3, 3), (4, 1)}

\left[\begin{array}{cccc}1&0&0&1\\0&1&0&0\\0&0&1&0\\1&0&0&0\end{array}\right]

for c) {(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)}

\left[\begin{array}{cccc}0&1&1&1\\1&0&1&1\\1&1&0&1\\1&1&1&0\end{array}\right]

for d d) {(2, 4), (3, 1), (3, 2), (3, 4)}

\left[\begin{array}{cccc}0&0&0&0\\0&0&0&1\\1&1&0&1\\0&0&0&0\end{array}\right]

Step-by-step explanation:

in matrix, arrays are placed in rows , which represents the horizontal sides from left to right, while arrays in the column are placed vertically from top to bottom. Here, we placed the arrays in a 4x4 matrix

for a  a) {(1, 2), (1, 3), (1, 4), (2, 3), (2, 4), (3, 4)}

\left[\begin{array}{cccc}0&1&1&1\\0&0&1&1\\0&0&0&1\\0&0&0&0\end{array}\right]

for b

b) {(1, 1), (1, 4), (2, 2), (3, 3), (4, 1)}

\left[\begin{array}{cccc}1&0&0&1\\0&1&0&0\\0&0&1&0\\1&0&0&0\end{array}\right]

for c) {(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)}

\left[\begin{array}{cccc}0&1&1&1\\1&0&1&1\\1&1&0&1\\1&1&1&0\end{array}\right]

for d d) {(2, 4), (3, 1), (3, 2), (3, 4)}

\left[\begin{array}{cccc}0&0&0&0\\0&0&0&1\\1&1&0&1\\0&0&0&0\end{array}\right]

7 0
3 years ago
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