Answer:
Minimum unit cost = 5,858
Step-by-step explanation:
Given the function : C(x)=x^2−520x+73458
To find the minimum unit cost :
Take the derivative of C(x) with respect to x
dC/dx = 2x - 520
Set = 0
2x - 520
2x = 520
x = 260
To minimize unit cost, 260 engines must be produced
Hence, minimum unit cost will be :
C(x)=x^2−520x+73458
Put x = 260
C(260) = 260^2−520(260) + 73458
= 5,858
Call (F) the age of the father and (J) the age of Julio
The F & J are related in this way: F=4J
Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.
Algebraically that is: F + J ≥ 55
You can substitute F with 4J to find the solution for J:
4J + J ≥ 55
5J ≥ 55
Now divide both sides by 5
5J/5 ≥ 55/5
J ≥ 11
That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
10*8=80
3*8=24
80-24=56
You would save $56.00 in 8 weeks
Answer:
14x+19x+8-8
=33x
because 8-8 is 0 always so the answer is 33X
Answer:
Step-by-step explanation:
<u>Total number of outcomes:</u>
<u>Number of combinations of getting 6 heads:</u>
- 15C6 = 15!/6!(15-6)! = 5005
<u>Required probability is:</u>
- P(6 heads out of 15 flips) = 5005/32768 = 0.1527... ≈ 15.3%
Correct choice is D
