Answer:
g(1)=-72; g(n)=g(n-1)*(1/6)
Step-by-step explanation:
g(1)= -72*(1/6)^(1-1)=-72*(1/6)^0=-72*1=-72
g(2)=-72*(1/6)^(2-1)=-72*(1/6)^1=-72*(1/6)=-12
g(2)=g(1)*(1/6)
g(n)=g(n-1)*(1/6)
20.4
If you are using D = r × t
10.2 = 0.5(t)
10.2/0.5 = t
20.4 = t
The formula of the sum of the arithmetic sequence:
We have:
substitute
16,30.34
