The inverse of that function would be 1/7x-3
X^2 - 7x + 12 = 0
x^2 - 4x - 3x + 12 = 0
x (x - 4) -3 ( x - 4) = 0
(x - 4) (x - 3) = 0
x = 3 , 4
Check the answer by plugging in 3 and 4 for x, if the equation equals zero then you have your answer.
Answer: the maximum is 25.
Step-by-step explanation: a max/min can occur on the endpoints of a function and critical points of the function's derivative.
f(x)=x^4-x^2+13
f'(x)=4x^3-2x
The critical points of f'(x) occur when f'(x) is zero or undefined. f'(x) is not ever undefined in this case, so we just need to find the x values for when it's zero.
0=4x^3-2x
x=.707, -.707
Now that we have the critical points of f'(x) (.707 and -.707) and endpoints (-1 and 2), we can plug in these x values into the original function to determine its maximum. When you do this you'll find that the greatest y value produced occurs when x=2 and results in a max of 25.
When dividing fractions the second term becomes the reciprocal
