There are 4 queens in the deck, hence (4 choose 2) = 4!/(2! (4-2)!) = 6 ways of getting 2 queens.
The other 3 cards in the deck can be any of the remaining 48 non-queens; there are (48 choose 3) = 48!/(3! (48-3)!) = 17,296 ways of getting these.
In total, there are (4 choose 2)*(48 choose 3) = 103,776 total possible hands.
Answer:
8, 9, 10, 11, 12
Step-by-step explanation:
Consecutive integer problems are often easier to work if you consider average values. Here, the middle of the 5 consecutive integers is their average, which is 50/5 = 10.
This tells you the integer side lengths are 8, 9, <em>10</em>, 11, 12.
Answer:
sana all may loptop hahhahhaha
The answer is B I believe
C. 2.4 x 10^6
D. 1.47 x 10^-3
I hope this helps !
