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3 years ago

I need help with this please help me

Mathematics

1 answer:

alex41 [277]3 years ago

4 0

To get green value 2 multiply by 7 because the yellow is 5 so to get 35 you have to multiply by 7.

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Find the volume of the cylinder

gizmo_the_mogwai [7]

Step-by-step explanation:

volume of cylinder formula pi*r²*h

radius of 9cm is 4.5 as 9/2

so 4.5²*15 is 303.75cm

303.75*pi is 303.75picm³

8 0

3 years ago

8p+8=10+7p what is the solution set

Evgesh-ka [11]

The answer is: "p = 2" .
______________________________________________________
Explanation:
______________________________________________________
Given:
______________________________________________________
" 8p + 8 = 10 + 7p " ; Solve for "p" ;

Subtract "7p" from each side of the equation; & subtract "8" from each side of the equation; as follows:

8p + 8 − 7p − 8 = 10 + 7p − 7p <span>− 8 ;
</span>
to get:
_________________________________________
"p = 2 " ; which is our answer.
_________________________________________

8 0

3 years ago

Read 2 more answers

Graph and label the image of the figure below after a dilation by a factor of 1/2.

neonofarm [45]

Answer:

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

see graph below

Explanation:

Given:

The image of a quadrilateral on a coordinate plane

To find:

The coordinates of the new image after dilation of 1/2 have been applied to the original image.

Then graph the coordinates

First, we need to state the coordinates of the original image:

M = (3, -2)

F = (4, -2)

L = (1, -5)

W = (5, -5)

Next, we will apply a scale factor of 1/2:

$\begin{gathered} Dilation\text{ rule:} \\ (x,\text{ y\rparen}\rightarrow(kx,\text{ ky\rparen} \\ where\text{ k = scale factor} \\ \\ scale\text{ factor = 1/2} \\ M^{\prime}\text{ = \lparen}\frac{1}{2}(3),\text{ }\frac{1}{2}(-2)) \\ M^{\prime}\text{ = \lparen}\frac{3}{2},\text{ -1\rparen} \\ \\ F\text{ = \lparen}\frac{1}{2}(4),\text{ }\frac{1}{2}(-2)) \\ F^{\prime}\text{ = \lparen2, -1\rparen} \end{gathered}$ $\begin{gathered} L\text{ = \lparen}\frac{1}{2}(1),\text{ }\frac{1}{2}(-5)) \\ L^{\prime}\text{ = \lparen}\frac{1}{2},\text{ }\frac{-5}{2}) \\ \\ W\text{ = \lparen}\frac{1}{2}(5),\text{ }\frac{1}{2}(-5)) \\ W^{\prime}\text{ = \lparen}\frac{5}{2},\text{ }\frac{-5}{2}) \end{gathered}$

The new coordinates:

M' (3/2, -1), F' (2, -1), L' (1/2, -5/2), W' (5/2, -5/2)

M' (1.5, -1), F' (2, -1), L' (0.5 -2.5), W' (2.5, -2.5)

Plotting the coordinates:

3 0

1 year ago

2[3(4^2 +1)] - 2^3.

Sav [38]

Answer:

Step-by-step explanation:

Do parentheses first, exponents inside them first. 4^2 = 16, + 1 is 17, then multiply by the 3 outside to get 51, then multiply by the 2 outside that to get 102, - 2^3 which is -8 = 94

7 0

3 years ago

Find the two numbers that have a sum of 49 and a difference of 1/2

NeX [460]

Answer:

$49.5 , -0.5$

Step-by-step explanation:

$a + b =49\\a - b = 0.5\\a= 49.5\\b= -0.5$

6 0

2 years ago

Read 2 more answers