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3 years ago

15

Consider a thermal energy reservoir at 1500 K that can supply heat at a rate of 150,000 kJ/h. Determine the exergy of this suppl

ied energy, assuming an environment temperature of 25°C.

1 answer:

ANEK [815]3 years ago

5 0

Answer:

exergy = 33.39 kW

Explanation:

given data

thermal energy reservoir T2 = 1500 K

heat at a rate = 150,000 kJ/h = $\frac{15000}{3600}$ kW = 41.67 kW

environment temperature T1 = 25°C = 298 K

solution

we get here maximum efficiency that is reversible efficiency is express as

reversible efficiency = 1 - $\frac{T1}{T2}$ ...............1

reversible efficiency = 1 - $\frac{298}{1500}$

reversible efficiency = 0.80133

and

the exergy of this supplied energy that is

exergy = efficiency × hat supply ................2

exergy = 0.80133 × 41.67 kW

exergy = 33.39 kW

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