Consider a thermal energy reservoir at 1500 K that can supply heat at a rate of 150,000 kJ/h. Determine the exergy of this suppl
1 answer:
Answer:
exergy = 33.39 kW
Explanation:
given data
thermal energy reservoir T2 = 1500 K
heat at a rate = 150,000 kJ/h = kW = 41.67 kW
environment temperature T1 = 25°C = 298 K
solution
we get here maximum efficiency that is reversible efficiency is express as
reversible efficiency = 1 - ...............1
reversible efficiency = 1 -
reversible efficiency = 0.80133
and
the exergy of this supplied energy that is
exergy = efficiency × hat supply ................2
exergy = 0.80133 × 41.67 kW
exergy = 33.39 kW
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Explanation:
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