The application of electro bioengineering uses principles of nick and computer science to design products is application of electrical engineering principles to biology, medicine, conduct, or health.
<h3>What is Bioelectronics?</h3>
- Bioelectronics is the application of electrical engineering principles to biology, medicine, conduct, or health.
- It advances the fundamental concepts, creates knowledge for the molecular to the organ techniques levels, and develops creative devices or methods for the deterrence, diagnosis, and treatment of disease, for patient rehabilitation, and for improving health.
- Bio electromagnetics, instrumentation, neural networks, robotics, and detector technologies are some of the disciplines necessary to develop new knowledge and creations in this area.
- A keystone of this research area is the building of and real-world devices and systems.
- Onsite facilities for prototyping and testing instrumentation systems, fabricating and measuring the performance of implantable devices, and making robotic prostheses, are readily available.
- New detectors and sensor arrays are microfabricated in a 2,000 sq ft cleanroom.
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Answer:
(b)False
Explanation:
defined as
=
Where x is the distance from centroidal x-axis
y is the distance from centroidal y-axis
dA is the elemental area.
The product of x and y can be positive or negative ,so the value of can be positive as well as negative .
So from the above expressions we can say that the product of 
is different from .
Answer:
it goes low to high off and on
Explanation:
because i wrote it
Answer:
The rate of vibrations of the atoms is consistent
Explanation:
A second is defined as 9,192,631,770 periods of the radiation corresponding to the transition between the two hyperfine levels of the ground state of the caesium 133 atom.
The definition applies when the atom is in isolation at a temperature of absolute zero. Adjustments must be made for the conditions that can be maintained in practice.
Such radiation is determined by the laws of quantum mechanics, so is extremely consistent.
Answer:
The speed is the same at 1.5 m/s while
The work done by the force F is 0.4335 J
Explanation:
Here we have angular acceleration α = v²/r
Force = ma = 2.8 × 1.5²/r₁
and ω₁ = v₁/r₁ = ω₂ = v₁/r₂
The distance moved by the force = 600 - 300 = 300 mm = 0.3 m
If the velocity is constant
The speed is 1.5 m/s while the work done is
2.8 × 1.5²1/(effective radius) ×0.3
r₁ = effective radius
2.8*9.81 = 2.8 × 1.5²/r₁
r₁ = 0.229
The work done by the force = 2.8 × 1.5²*1/r₁ *0.3 = 0.4335 J
